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2 years ago

Find the slope of the line shown in the graph a.3 b.-1 c.-1/3 d.1/3

Mathematics

2 answers:

Oliga [24]2 years ago

7 0

The answer is 1/3 because of rise over run

Marat540 [252]2 years ago

4 0

Answer:

-1/3

Step-by-step explanation:

it goes up by one so -1 then to the right 3 so 3 that means the slope is -1/3

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EXAMPLEA Find the surface area of the rectangular prism. 6 m 8 m 3 m

Mama L [17]

Answer:

180 m²

Step-by-step explanation:

Surface area = 2 ( lw + wh + lh)

= 2( 6x3 + 3x8+8x6)

= 180 m²

6 0

3 years ago

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Please answer this correctly without making mistakes

Gekata [30.6K]

Answer:

Step-by-step explanation:

The distance is given by

d = sqrt( (x2-x1) ^2 + ( y2-y1) ^2)

Since the x values are the same

d = sqrt( ( y2-y1) ^2)

d = sqrt( (( -6 - 10)^2))

d = sqrt((-16) ^2)

d = 16

We can also just find the number of squares between the points since the x value is the same.

10 - -6

10+6

4 0

2 years ago

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2. Write 7x2 - 4 + 6x3 - 4x - x4 in standard form.

Hunter-Best [27]

Answer:

16-5x

Step-by-step explanation:

5 0

3 years ago

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5x+2y=7 as a ordered pair

Elenna [48]

(1, 1), 5 + 2 = 7, not that hard!

8 0

3 years ago

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The area of a mirror is 225 Square inches, it's width is

Zepler [3.9K]

NO. The mirror will not fit in a space that is 15 inches by 16 inches

Solution:

Given that area of mirror is 225 square inches

$width = 13\frac{3}{4} \text{ inches }$

Converting the above mixed fraction we get,

$width = 13\frac{3}{4} = \frac{13 \times 4 + 3}{4} = \frac{55}{4} \text{ inches }$

Let us find the length of mirror

The area of mirror is given as:

area of mirror = length x width

Substituting the given values,

$225 = length \times \frac{55}{4}\\\\length = 225 \times \frac{4}{55}\\\\length = 225 \times 0.0727\\\\length = 16.36$

Thus length of mirror is 16.36 inches

Will the mirror fit in a space that is 15 inches by 16 inches?

NO. The mirror will not fit in a space that is 15 inches by 16 inches

Because length of mirror is 16.36 inches whereas the given space is 15 inches long

16.36 > 15 so the length of mirror will not fit inside the space

Also width of mirror is $\frac{55}{4} = 13.75$ inches which is less than the given space whose width is 16 inches

13.75 < 16 so the width of mirror will not fit inside the space

7 0

3 years ago