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gtnhenbr [62]
3 years ago
10

Mona wrote 7 tests, and her test average is 93. There will be one more test before the end of the year. What is the lowest grade

that Mona can get for her last test so that her test average is 90 or more?
Mathematics
1 answer:
olga55 [171]3 years ago
8 0
For this case, the first thing we are going to do is assume that all the tests are worth the same.
 Then, we define a variable:
 x: score of Mona's last test
 We write now the inequality that models the problem:
 \frac{93 + x}{2}  \geq  90
 From here, we clear the value of x: 93 + x  \geq  90*(2) 

93 + x  \geq  180

 x  \geq  180 - 93

 x  \geq  87
 Answer:
 
the lowest grade that Mona can get for her last test so that her test average is 90 or more is:
 
x = 87
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4 0
3 years ago
Read 2 more answers
Please help explanation if possible
egoroff_w [7]

Answer: x = 2 and y = -4

x + 2y = -6

x = -6-2y

Putting this in value of x in

6x + 2y = 4

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-36-12y+2y = 4

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y = 40/(-10)

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Now putting this value of y in

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Therefore x = 2 and y = -4

If we put these values we can check this

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2 -8 = -6

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please click thanks and mark brainliest if you like :)

7 0
2 years ago
Read 2 more answers
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