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evablogger [386]
2 years ago
11

Add and simplify

Mathematics
1 answer:
Tanya [424]2 years ago
6 0

Answer:

Your 1st answer is correct

Step-by-step explanation:

\frac{1}{(x - 1)}  -  \frac{3}{(1 - x)}   + 2

\frac{1}{(x - 1)}  -  \frac{3}{ - (x - 1)}  + 2

\frac{1}{(x - 1)}   +  \frac{3}{(x - 1)}  + 2

\frac{4}{(x - 1)}  + 2

\frac{4 + 2(x - 1)}{x - 1}

\frac{4 + 2x - 2}{x - 1}

= \frac{2x  + 2}{x - 1}

=  \frac{2(x + 1)}{x - 1}

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Ann [662]

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

<h3>How to determine the rational root of the function f(x)?</h3>

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

For a function P(x) such that

P(x) = ax^n +...... + b

The rational roots of the function p(x) are

Rational roots = ± Possible factors of b/Possible factors of a

In the function f(x), we have:

a = 3

b = 6

The factors of 3 and 6 are

a = 1 and 3

b = 1, 2, 3 and 6

So, we have:

Rational roots = ±(1, 2, 3, 6)/(1, 3)

Split the expression

Rational roots = ±(1, 2, 3, 6)/1 and ±(1, 2, 3, 6)/3

Evaluate the quotient

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3, 1, 2)

Remove the repetition

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3)

Hence, the rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

The complete parameters are:

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

Read more about rational roots at

brainly.com/question/17754398

#SPJ1

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