The sum of probability for an event happening and not happening must be equal to 1 because there is a 100% chance that one or the other will occur.
So the probability on not drawing a quarter:
P(!Q)=1-4/5
P(!Q)=5/5-4/5
P(!Q)=1/5
As a percentage:
p/100=1/5
p=100/5
p=20%
Answer:
A rectangle with a length of 6 and width of 2.
The corners added up make a rectangle so it is the same as a rectangle. You can just multiply 6 x 2 = 12 to find the area. If you have any more questions you are welcome to ask
Step-by-step explanation:
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
Answer:
0.026
Step-by-step explanation:
Given the result of 10 coin flips :
T,T,H,T,H,T,T,T,H,T
Number of Heads, H = 3
Number of tails, T = 7
Let :
B = biased coin
B' = non-biased coin
E = event
Probability that it is the biased coin:
P(E Given biased coin) / P(E Given biased coin) * P(E Given non-biased coin) * P(non-biased coin)
P(E|B)P(B) / (P(E|B)*P(B) + P(E|B')P(B')
([(0.75^3) * (0.25^7)] * 0.5) /([(0.75^3) * (0.25^7)] * 0.5) + (0.5^10) * 0.5
0.0000128746 / 0.00050115585
= 0.0263671875
