Answer:
Solution given:
BD=35ft
AC=43ft
AB=8ft
EF=33-8=25ft
AE=26ft
Now
area of right angled triangle ∆AEF
=½(EF*AE)=½(25×25)=312.5ft²
area of parallel trapezoid=½AB(BD+AC)
=½*8(35+43)=312ft²
<u>So</u>
<u>Area</u><u> </u><u>of</u><u> </u><u>polygon</u><u> </u><u>:</u><u> </u><u>3</u><u>1</u><u>2</u><u>.</u><u>5</u><u>+</u><u>3</u><u>1</u><u>2</u><u>=</u><u>6</u><u>2</u><u>4</u><u>.</u><u>5</u><u>f</u><u>t</u><u>²</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Answer: Bajo del Gualicho has a higher elevation than Lago Enriquillo.
Step-by-step explanation:
Since in this case the "elevations" are negative because are under sea level, we can call it depth.
In this sense, we are given the "elevations" or depths of two places:
Bajo del Gualicho: -72 m
Lago Enriquillo: -46 m
Keeping in mind we are actually talking about the depth of this places, we can say Bajo del Gualicho is deeper than Lago Enriquillo, and this is best expressed with the following inequality:

Where
represents Bajo del Gualicho and
represents Lago Enriquillo.
Answer:
<em>y=7x+1</em>
Step-by-step explanation:
<u>Linear modeling</u>
Consists of finding a linear equation that represents a situation in real life.
Jenny starts her stamps collection with only 1 stamp.
Then she collects 7 stamps per day.
Let's call
y=total amount of stamps in Jenny's collection
x=number of days
Knowing Jenny collects 7 stamps per day, then in x days, she collects 7x stamps. The total amount can be obtained by adding the first stamp she had. Thus, the model is:
y=7x+1
<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases

Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0
and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0
and g2 = 9.8
We get h1 = 3.67m which is the required height
Answer:
n = 9/4 = 2.250
Step-by-step explanation:
Rearrange: 4*n-(9)=0
Solve: 4n-9 = 0
4n = 9
n = 9/4 = 2.250
answer: n = 9/4 = 2.250