If two dices are rolled once, you would have a total number of 6*6=36 possibilities.
To get a sum greater than 10:
A) one of your dices could be showing a 5, the other a 6. That’s two possibilities. Dice A being the 5 or dice B being the 5.
B) both of your dices could be showing 6s.
That’s one possibility.
So your overall possibility to get a sum greater than 10 is (1+2)/36 3/36=1/12
One twelfth.
Answer:
16.3 N
Step-by-step explanation:
subtract if the forces are opposite
Attendance with the higher ticket price is ...
... $1750/$7 = 250
So the percentage change in attendance is ...
... change = (new - original)/original × 100%
... = (250 -300)/300 × 100% = -1/6×100% ≈ -17%
2(x-3)=2x-6 This is distributive property.
2(x-3)= 2x - 2*3 = 2x-6
It's not time to try and simplify it until you HAVE an equation. You won't have an equation until you write down what. V*4x is equal to.
