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2 years ago

If f(x)=x+2,g=(x)=4x-1,fg(2)?

Mathematics

1 answer:

zysi [14]2 years ago

8 0

Answer:

$f(x) = x + 2 \\ g(x) = 4x - 1 \\ find \: fg(2) \\ therefore \: fg(2) = 2 + 2 + 4(2) - 1 \\ fg(2) =8(2)-1 \\fg(2)=16-1 \\ fg(2)= 15$

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Dima020 [189]

Answer:

Step-by-step explanation:

11+5=16

16 x 6=96

7 0

3 years ago

Read 2 more answers

Two thirds of the parade vehicles were vintage vehicles and 1⁄3 of the vintage vehicles were motorcycles. What fraction of the t

Liula [17]

Answer:the fraction of the total parade vehicles that are motorcycles is 2/9

Step-by-step explanation:

Let x represent the total number of parade vehicles.

Two thirds of the parade vehicles were vintage vehicles. This means that the total number of vintage vehicles would be

2/3 × x = 2x/3

1⁄3 of the vintage vehicles were motorcycles. This means that the total number of motorcycles would be

1/3 × 2x/3 = 2x/9

Therefore, the fraction of the total parade vehicles that are motorcycles would be

2x/9/x = 2/9

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2 years ago

Find dy/dx by implicit differentiation. y cos x = 5x2 + 3y2

lbvjy [14]

Step 1:
Start by putting $\frac{d}{dx}$ in front of each term

$\frac{d}{dx}[y cos x]= \frac{d}{dx}[5x^2]+ \frac{d}{dx}[ 3y^2]$
-----------------------------------------------------------------------------------------------------------------
Step 2:

Deal with the terms in 'x' and the constant terms
$\frac{d}{dx}[ycosx]= 10x+ \frac{d}{dx} [3y^2]$
----------------------------------------------------------------------------------------------------------------
Step 3:

Use the chain rule for the terms in 'y'
$\frac{d}{dx}[ycosx]=10x+6y \frac{dy}{dx}$
--------------------------------------------------------------------------------------------------------------
Step 4:

Use the product rule on the term in 'x' and 'y'
$(y) \frac{d}{dx} cos x+(cos x) \frac{d}{dx}y =10x+6y \frac{dy}{dx}
$
$y(-siny)+(cosx) \frac{dy}{dx} =10x+6y \frac{dy}{dx}$
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Step 5:

Rearrange to make $\frac{dy}{dx}$ the subject
$-y sin(y)+cos(x) \frac{dy}{dx} =10x+6y \frac{dy}{dx}$
$cos(x) \frac{dy}{dx}-6y \frac{dy}{dx}=10x+y sin(y)$
$[cos(x) - 6y] \frac{dy}{dx}=10x + y sin(y)$
$\frac{dy}{dx}= \frac{10x+ysin(y)}{cos(x)-6y}$ ⇒ Final Answer

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3 years ago

A car traveled 180 miles at a constant rate. Write an equation that would

Mnenie [13.5K]

Answer:

180/t = r

Step-by-step explanation:

In this question, we would have to write an equation that represents the scenario given.

We know that the car traveled 180 miles at a constant rate.

We would use the y = mx + b format for the equation, but replacing the variables with "r" and "t"

We know that 180 will be our y-variable, since that would be the base of the equation:

180 = ???

And to find how long/fast it will take the car, we would need to multiply the rate of speed "r" and time "t" in order to get our distance.

Plug it into the equation:

180 = rt

With this set up, you can find the rate of speed of the car when you know the time.

You would simply solve it as:

180/t = r

7 0

3 years ago

Please help I will give a medal

Tanya [424]

Funtion ! in vertex form is given by
<span>f(x) = 4x^2 + 8x + 1</span> = 4(x^2 + 2x + 1/4) = 4(x^2 + 2x + 1 + 1/4 - 1) = 4(x + 1)^2 + 4(-3/4) = 4(x + 1)^2 - 3
Thus, the least minimun value is (-1, -3)
Also, the least minimum value of function 2 is (-1, 0)

Therefore, function 1 has the least minimum value at (-1, -3)

4 0

2 years ago

Read 2 more answers

If f(x)=x+2,g=(x)=4x-1,fg(2)?​

If f(x)=x+2,g=(x)=4x-1,fg(2)?