If f(x)=x+2,g=(x)=4x-1,fg(2)?

Mathematics

1 answer:

zysi [14]2 years ago

8 0

Answer:

$f(x) = x + 2 \\ g(x) = 4x - 1 \\ find \: fg(2) \\ therefore \: fg(2) = 2 + 2 + 4(2) - 1 \\ fg(2) =8(2)-1 \\fg(2)=16-1 \\ fg(2)= 15$

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k0ka [10]

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Step-by-step explanation:

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3 years ago

John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart

Rina8888 [55]

<h2>Answer:</h2>

$Probability=\frac{1}{24}$

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

$Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}$

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is $\frac{1}{24}$ </u></em>

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3 years ago

To control the traffic during Ramadan month, a Police Sergeant is assigned to control the traffic

m_a_m_a [10]

To complete the table it is necessary to know the possibilities that the sergeant has to change or remain in an intersection. The probabilities (depending on the box) are:

0
0.2
0.25
0.33

<h3>How to calculate the probability of intersection change? </h3>

To know the probability of intersection change, it is necessary to locate the police officer at one of the intersections. Subsequently, count how many possibilities of change you have, for example: 3 possibilities and finally add the possibility of remaining in the intersection as shown below:

Intersection 3 has 3 possibilities of changing towards intersections 2, 8 and 4. Additionally, it has the possibility of staying at intersection 3, that is, it has 4 possible decisions.

To know the probability we divide the number 1 (because it is only a decision that we have to make) and divide it by the number of possibilities (4).

1 ÷ 4 = 0.25

According to the image we can infer that in some intersections they only have 3, 4 and 5 possibilities, so the probability of change will be different as shown below: