2 years ago

If f(x)=x+2,g=(x)=4x-1,fg(2)?

1 answer:

zysi [14]2 years ago

8 0

Answer:

$f(x) = x + 2 \\ g(x) = 4x - 1 \\ find \: fg(2) \\ therefore \: fg(2) = 2 + 2 + 4(2) - 1 \\ fg(2) =8(2)-1 \\fg(2)=16-1 \\ fg(2)= 15$

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Alex787 [66]

Answer:

Step-by-step explanation:

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3 years ago

Travka [436]

Answer:

$S_5=\dfrac{170}{9}$

Step-by-step explanation:

Given that,

The sum of first n term of a sequence is $S_n=20-\dfrac{10}{2n-1}$

We need to find the sum of the first 5 terms.

Put n = 5,

$S_5=20-\dfrac{10}{2(5)-1}\\\\=20-\dfrac{10}{10-1}\\\\=20-\dfrac{10}{9}\\\\=\dfrac{170}{9}$

So, the sum of first 5 terms is equal to $\dfrac{170}{9}$ .

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3 years ago

S_A_V [24]

So you cant have a decimal in your divisor which means the problem sill become 18215/7 if that helps

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3 years ago

elena55 [62]

All I know or all I understood was both 7 and 8 aren’t functions. Hope this helped

4 0

3 years ago

Elanso [62]

<span>I got 2^(3/5) as the answer</span>

8 0

3 years ago

If f(x)=x+2,g=(x)=4x-1,fg(2)?​