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Degger [83]
3 years ago
15

Point P on the coordinate grid below shows the location of a stage light. A second stage light is 8 units above P. The length of

each square on the grid is 2 units. What
are the coordinates of the location of the second stage light?
O (4.6)
O (4.-10)
(12,6)
(12.-10)
Mathematics
1 answer:
erastovalidia [21]3 years ago
4 0

Answer: Is (12.-10) I think

Step-by-step explanation:

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Answer:

4 altogether

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Step-by-step explanation:

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kumpel [21]

Answer:

(x+4)^2+(y-3)^2=149

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center of the circle and r is the radius of the circle.

Given that (h,k)\rightarrow(-4,3) and it passes (6,-4), their distance between each other must the radius of the circle, so we can use the distance formula to find the radius:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(-4-3)^2+(6-(-4))^2}\\\\d=\sqrt{(-7)^2+10^2}\\\\d=\sqrt{49+100}\\\\d=\sqrt{149}

Therefore, if the length of the radius is r=\sqrt{149} units, then r^2=149, making the final equation of the circle (x+4)^2+(y-3)^2=149

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What is 2+2-3+9-5+3=
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Answer:

8

Step-by-step explanation:

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The correct answer is D.

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