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VikaD [51]
3 years ago
9

You can mow 2 acres of your field in an hour and

Mathematics
1 answer:
alekssr [168]3 years ago
8 0

Answer: I think the answer is 8hrs and 30 minuets

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Solve the following quadratic equation for all values of xx in simplest form. 16+2x²=30​
Katarina [22]

Link Provided in other answer is a SCAM !!! Do NOT CLICK ON IT !!!
6 0
3 years ago
This year, a small business had a total revenue of $45,000. If this is 25% less than their total revenue the previous year, what
morpeh [17]

Let R = total revenue the year before

R = 45,000 x 0.25 + 45,000

R = 11,250 + 45,000

R = $56,250

7 0
3 years ago
Find the balance in the account.<br> $3,800 principal earning 2%, compounded annually, after 7 years
sineoko [7]

Answer:

A = $4360.515918 which rounded to the nearest penny is $4360.52

Step-by-step explanation:

8 0
2 years ago
The half- life of 1-137 is 8.07 days.if 100 grams are left after 40.35 days, how much grams were in the original sample?
a_sh-v [17]

Answer:

8L/2days  = 4L/day

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Step-by-step explanation:

3 0
3 years ago
Determine whether the series is absolutely convergent 1-(1*3/3! (1*3*5/5!-(3*5*7)
DENIUS [597]
It's not clear what your series is, so I'm going to take a wild guess on what it is you mean:

1-\dfrac{1\times3}{3!}+\dfrac{1\times3\times5}{5!}-\dfrac{1\times3\times5\times7}{7!}+\cdots
=\displaystyle\sum_{n=1}^\infty\frac{(-1)^{n-1}}{(2n-1)!}\prod_{k=1}^n(2k-1)

For the sum to be absolute convergent, the sum of the absolute value of the summand must converge, so you are really examining the convergence of

\displaystyle\sum_{n=1}^\infty\frac1{(2n-1)!}\prod_{k=1}^n(2k-1)

This is easily checked with the ratio test:

\displaystyle\lim_{n\to\infty}\left|\frac{\displaystyle\dfrac1{(2(n+1)-1)!}\prod_{k=1}^{n+1}(2k-1)}{\displaystyle\dfrac1{(2n-1)!}\prod_{k=1}^n(2k-1)}\right|=\lim_{n\to\infty}\left|\frac{\dfrac{1\times3\times5\times\cdots\times(2n-1)\times(2n+1)}{(2n+1)!}}{\dfrac{1\times3\times5\times\cdots\times(2n-1)}{(2n-1)!}}\right|
\displaystyle=\lim_{n\to\infty}\left|\frac{\dfrac{2n+1}{(2n+1)(2n)}}{\dfrac11}\right|=\lim_{n\to\infty}\dfrac1{2n}=0

Since \sum|a_n| converges by the ratio test, the series \sum a_n converges absolutely.
4 0
2 years ago
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