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DedPeter [7]
3 years ago
11

1962÷18 whats the answer show working​

Mathematics
1 answer:
nadezda [96]3 years ago
7 0

Answer:

109

Step-by-step explanation:

Download pdf
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What quantity could go in the blank to make the equation below true? Equation: n + n + ____ = 4n
rosijanka [135]

Answer:

4

Step-by-step explanation:

5 0
3 years ago
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F(x) = x2. What is g(x)?<br><br> pls help it’s due soon!!
qwelly [4]

Answer:

A. g(x) = (2x)²

Step-by-step explanation:

From the diagram of the two functions graph f(x) is the parent function and g(x) is the transformed function. you can see that the graph of g(x) is stretched vertically compared to the graph of g(x). The Parent function has y =1 corresponding to x =1 while for the transformed function when x = 1, y = 4 the graph is vertically stretched by a factor of 4, and horizontally The Parent function has y =1 corresponding to x =1. while for the transformed function when x = 0.5, y = 1, it is stretched  horizontally by 2 (√4), i.e

This means that g(x) = 4x² = (2x)²

6 0
3 years ago
Julie drew a picture of her rectangular garden,. In her picture,the length of her garden is 7/8 inches and the width is 3/4 inch
stepan [7]

Answer:

21/32 square inches.


Step-by-step explanation:

The area of a rectangle = length x width

The area of her picture = length x widht

= 7/8 x 3/4

= 21/32

The area of her picture is 21/32 square inches.

Yes, I agree the area of the picture is 21/32 square inches.

The area must be in square inches. So she need to specify it.

Thank you.

5 0
3 years ago
If you wanted to purchase new sneakers originally priced at $78 and the cashier
Triss [41]

Answer:

You are paying 8 percent of tax

8 0
3 years ago
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The volume of a box is 5x^3 + 20x^2 + 15x cm^3. If the height of the box is 5x cm, find the width and length of the box.
Annette [7]

Answer:

The product of the Width and Length is x^2 + 4x + 3 cm^2.

Step-by-step explanation:

The volume of a box = 5x^3 + 20x^2 + 15x cm^3.

Volume of a Box = W*L*H       [Width(W), Length(L), and Height(H)]

W*L*(5x) = 5x^3 + 20x^2 + 15x cm^3

W*L = (5x^3 + 20x^2 + 15x cm^3)/5x cm

W*L = x^2 + 4x + 3 cm^2

We know the area of the base of the box (W*L).  It is x^2 + 4x + 3 cm^2.

To find the actual width and length, we need to know one of the variables, L or W.  Without that, all we can say is that their product (W*L) is x^2 + 4x + 3 cm^2.

8 0
2 years ago
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