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DedPeter [7]
2 years ago
11

1962÷18 whats the answer show working​

Mathematics
1 answer:
nadezda [96]2 years ago
7 0

Answer:

109

Step-by-step explanation:

Download pdf
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Lin counts 5 bacteria under a microscope. She counts them again each day for four days, and finds that the number of bacteria do
Liula [17]

Answer:

The population of bacteria can be expressed as a function of number of days.

Population = \[5*2^{n-1}\] where n is the number of days since the beginning.

Step-by-step explanation:

Number of bacteria on the first day=\[5 * 2^{0} = 5\]

Number of bacteria on the second day = \[5 * 2^{1} = 10\]

Number of bacteria on the third day = \[5*2^{2} = 20\]

Number of bacteria on the fourth day = \[5*2^{3} = 40\]

As we can see , the number of bacteria on any given day is a function of the number of days n.

This expression can be expressed generally as \[5*2^{n-1}\] where n is the number of days since the beginning.

6 0
3 years ago
Pls help me!!!!!! ASAP
snow_lady [41]

I need the whole picture that’s only half

7 0
3 years ago
Please help find the probability that x >25.
bija089 [108]

Answer

The total probability is one:

Total probability of being greater than 25 is 1 because the totals of all values less than 25 is 1.

5 0
2 years ago
2 Which expression is equivalent to 64-*?
Rasek [7]

Answer:

2

Step-by-step explanation:

(8-x)(8+x)

8×8=64

-x·+x=-x^2

64-x^2

3 0
2 years ago
An admiral, captain, and commander, all different, are to be chosen from a group of 10 Starfleet officers. How many different ch
zepelin [54]

Answer:

10C1 *9C1*8C1 = 10*9*8=720

Step-by-step explanation:

For this case in order to select the one admiral, captain and commander, all different. We are assuming that the order in the selection no matter, so we can begin selecting an admiral then a captain and then a commander.

So we have 10C1 ways to select one admiral since we want just one

Now we have remaining 9 people and we have 9C1 ways to select a captain since we want a captain different from the admiral selected first

Now we have remaining 8 people and we have 8C1 ways to select a commander since we want a commander different from the captain selected secondly.

The term nCx (combinatory) is defined as:

nCx = \frac{n!}{x! (n-x)!}

And by properties nC1= n

So then the number of possible way are:

10C1 *9C1*8C1 = 10*9*8=720

If we select first the captain then the commander and finally the admiral we have tha same way of select 10*9*8=720

For all the possible selection orders always we will see that we have 720 to select.

5 0
2 years ago
Read 2 more answers
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