The legs of a right triangle measure 15 and 20. what is the length of the hypotenuse?

1 answer:

7 0

it depends on how big the triangle is if it is close to the same length of 20 go with 25 if theres a bigger difference go with 35. I think it would be 25 tho.

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What would the answer to this question be? show work please

AURORKA [14]

Answer:

Step-by-step explanation:

The volume of a rectangular prism is the length times width times height.

V = LWH

V = (4√3)(3√6)W

V = 12√18 W

V = 36√2 W

If the volume is irrational, then W cannot have a radical that is half of a perfect square, because when multiplied by √2, that would yield a rational volume. For example, √18 × √2 = √36 = 6.

Therefore, the answer must be B, because 12 is not half of a perfect square.

V = 36√2 (4√12)

V = 144√24

V = 288√6

5 0

3 years ago

If 7x+10=44, what is the value of 7x-50?

Daniel [21]

Answer:

-16

Step-by-step explanation:

So let’s solve for 7x. So 7x=34. So 7x-50 is 34-50 or -16

6 0

3 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$