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expeople1 [14]
3 years ago
10

The legs of a right triangle measure 15 and 20. what is the length of the hypotenuse?

Mathematics
1 answer:
Stells [14]3 years ago
7 0

it depends on how big the triangle is if it is close to the same length of 20 go with 25 if theres a bigger difference go with 35. I think it would be 25 tho.

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The following question has two parts. First, answer part A. Then, answer part B.
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Answer:

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  Part B:  see below

Step-by-step explanation:

<u>Part A</u>:

13.245 rounded to tenths is 13.2

<u>Part B</u>:

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The area of a rectangle garden is 2g^2+34g+140. If the width is 2g+14 what is the length?
ASHA 777 [7]
We know  that
[area of rectangle]=length*width
area=2g²<span>+34g+140
</span><span>width =2g+14
</span>
step 1
find the roots of 2g²+34g+140

using  a graph tool-----> to resolve the second order equation
see the attached figure
the solution is 
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g=-7
so
2g²+34g+140=(2g+14)*(g+10)

therefore

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the answer is
the length is (g+10)

3 0
3 years ago
If the area of AABC is D, give the expressions that complete the equation for the measure of ZB?
Ira Lisetskai [31]

Given:

The figure of triangle ABC.

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m\angle B=\sin ^{-1}(\dfrac{m}{n})

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

Area=\dfrac{1}{2}\times base\times h

Where, b is the base and h is the height of the triangle.

Area=\dfrac{1}{2}\times a\times h

The area of the triangle ABC is D.

D=\dfrac{1}{2}\times a\times h

2D=ah

\dfrac{2D}{a}=h                  ...(i)

In a right angle triangle,

\sin \theta =\dfrac{Perpendicular}{Hypotenuse}

\sin B =\dfrac{h}{c}

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\sin B =\dfrac{2D}{ac}

m\angle B =\sin ^{-1}\dfrac{2D}{ac}            ...(ii)

We have,

m\angle B=\sin ^{-1}(\dfrac{m}{n})          ...(iii)

On comparing (ii) and (iii), we get

m=2D

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3 years ago
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nordsb [41]

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Step-by-step explanation:

in standard form

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