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Aleks [24]
3 years ago
14

HELP??

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

2 prices are at or below $39.99

4 prices are at or above $40

4 prices are between $29.99 and $70

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Evaluate log38, given log32 ≈ 0.631.
ArbitrLikvidat [17]
\log_38-\log_32^3=3\log_32\approx3\cdot0.631=1.893\\\\Used:\log_ab^n=n\cdot\log_ab
4 0
3 years ago
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Find two consecutive intergers whose sum is -29
boyakko [2]
-29= x + (x + 1)
-29= 2x +1
-30= 2x
-15=x
The answer is -15, -14.
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3 years ago
Hank is buying new curtains for his house. Each window will need 2 curtains panels to cover it. He has a total of 16 windows in
fenix001 [56]

Answer:

He spends $298

Step-by-step explanation:

He has 16 curtains

16*2=32

That answer is how many he needs

Now multiply that by the price

32 curtains for $29

32*29=928

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Find the missing angle please!!
beks73 [17]
Step 1: All angles in a triangle must add up to 180! Therefore, in the upper triangle, add up the two you know 85+35=120 so the missing angle is 60.
Step 2: Bottom triangle. Your new angle above (60) is the pair of the opposite angle - so it too is 60. So now you know 2 of the 3 angles: 60+64=124 Subtract that from 180 and you get 56...which is the answer for ?
8 0
3 years ago
Can anyone tell me why by direct substitution of x, the equation (circled ones) equals to the indeterminate form, 0/0? When you
Katena32 [7]

Answer:

See explanation and hopefully it answers your question.

Basically because the expression has a hole at x=3.

Step-by-step explanation:

Let h(x)=( x^2-k ) / ( hx-15 )

This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.

Solving for x in that equation:

Adding 15 on both sides:

hx=15

Dividing both sides by h:

x=15/h

For it be a hole, you also must have the numerator is zero at x=15/h.

x^2-k=0 at x=15/h gives:

(15/h)^2-k=0

225/h^2-k=0

k=225/h^2

So if we wanted to evaluate the following limit:

Lim x->15/h ( x^2-k ) / ( hx-15 )

Or

Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.

We were ask to evaluate

Lim x->3 ( x^2-k ) / ( hx-15 )

Comparing the two limits h=5 and k=225/h^2=225/25=9.

3 0
3 years ago
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