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ycow [4]
3 years ago
5

Find two numbers whose sum is 64 and whose difference is 42

Mathematics
1 answer:
vovangra [49]3 years ago
4 0
These numbers are  "a"  and "b".  
Sum is 64,  so  a+b=64
Difference  is 42  so  a-b=42
So you've got:
+\begin{cases} a+b=64 \\ a-b=42\end{cases} \\ \overline{, \quad2a \quad \ = \ 106} \qquad /:2 \\ a=53
When a+b=64 and a=53  you've got:
53+b=64
b=11

So these numbers is 53 and 11. 

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<em>Last year the chess club had 30 members. This year the club has 24 members. </em>

Last year, the chess club had 30 members. This year, the club has 24 members. Since this year had less than last year ( 30 > 24), the percent will be decreasing.

To find the percent decrease, you have to use the following formula.

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Difference refers to the difference between the two numbers, 24 and 30. The difference between 24 and 30 is 6. Original refers to the original number, which is last year's amount of members in the chess group. Therefore, original = 30.

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Since I started off by identifying whether it was decreasing or increasing, I did the work a bit differently. When finding the difference, you would usually subtract 30 from 24, which results in -6. Above I used 6, but if you used -6, you would end up with a result of -20%, which means it decreased by 20%. They bot end up with the same result, but you don't always have to first identify whether it's decreasing or increasing.

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