Answer:
4, 1, 6.
See explanation
Step-by-step explanation:
You are given the equation
![d=vt-\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=d%3Dvt-%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
First subtract
from both sides:
![d-vt--\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=d-vt--%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
and multiply the equation by -1:
![vt-d=\dfrac{1}{2}at^2\ \ \ \ (1)](https://tex.z-dn.net/?f=vt-d%3D%5Cdfrac%7B1%7D%7B2%7Dat%5E2%5C%20%5C%20%5C%20%5C%20%281%29)
Now multiply (1) by 2:
![2(vt-d)=at^2\ \ \ \ \ (2)](https://tex.z-dn.net/?f=2%28vt-d%29%3Dat%5E2%5C%20%5C%20%5C%20%5C%20%5C%20%282%29)
At last, divide by ![a](https://tex.z-dn.net/?f=a)
![t^2=\dfrac{2(vt-d)}{a}\ \ \ \ \ (3)](https://tex.z-dn.net/?f=t%5E2%3D%5Cdfrac%7B2%28vt-d%29%7D%7Ba%7D%5C%20%5C%20%5C%20%5C%20%5C%20%283%29)
Answer:
Think about what number you got multiply 7 to get 28. Once you do, multiply the other numbers by that digit
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Answer:
I would tell you
Step-by-step explanation:
you need to put 2 y and 2 x and that you need to divide