- <u>Jan </u><u>purchased </u><u>1</u><u>4</u><u>0</u><u> </u><u>shares </u><u>of </u><u>stock </u><u>in </u><u>ABC </u><u>company </u><u>at </u><u>a </u><u>price </u><u>of </u><u>$</u><u>1</u><u>8</u><u>.</u><u>7</u><u>5</u><u> </u><u>per </u><u>share </u>
- <u>During </u><u>the </u><u>next </u><u>3</u><u> </u><u>days</u><u>, </u><u> </u><u>the </u><u>value </u><u>of </u><u>share </u><u>declined </u><u>by </u><u>$</u><u>1</u><u>.</u><u>0</u><u>0</u><u> </u><u>,</u><u> </u><u>$</u><u>1</u><u>.</u><u>7</u><u>5</u><u> </u><u>and </u><u>$</u><u>1</u><u>.</u><u>5</u><u>0</u>
- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>a </u><u>share </u><u>of </u><u>ABC </u><u>stock </u><u>at </u><u>the </u><u>end </u><u>of </u><u>3</u><u> </u><u>days </u>
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>
Cost of 1 share of ABC company = $18.75
<u>Therefore</u><u>, </u>
Cost of 140 shares purchased by Jan in the ABC company
<u>Now</u><u>, </u>
For next 3 days, the value of share declined
<u>Therefore</u><u>, </u>
The value of shares after 3 days will be
Hence, The value of share after 3 days will be $18.75 .
Answer:
x = 1 and y = 4
Step-by-step explanation:
m² = 7x + 7; m³= 4y and m∧4 = 112
√(m∧4) = √112
∴ m² = √112
Hence, 7x + 7 = √112
(7x + 7)² = 112
49x² + 14x + 49 = 112
49x² + 14x - 63 = 0
7x² + 2x - 9 = 0
7x² + 9x - 7x - 9 = 0
x(7x + 9) - 1(7x + 9) = 0
(x - 1)(7x + 9) = 0
x - 1 = 0
∴ x = 1
When x = 1
m²= 7 + 7 = 14
m³= 4y and m∧4 = 112
Also m∧4/m²= m² = 112/14 = 8
Hence, m° = 2; m = 2 X 2 = 4; m² = 2 x 2 x 2 = 8; m³= 2 x 2 x2 x 2 = 16
m³ = 16 = 4y
∴ y = 16/4 = 4
Answer:
Natalie arrived at 3:55 pm or 15:25
Step-by-step explanation:
Start time is 3:00
The first two friends arrived at 10 minutes after 3. Arrival time = 3:10
Natalie arrived 45 minutes later. Arrival time is 3:10 + 45 = 3:55
Natalie arrived at 3:55, using 24-hour formats, the arrival time is 15:55