Question

I need help with these three equations 3x - 2 = x + 10 X+4=19-2x 8z - 20 =z +15

Answer 1

Answer:

1st answer is 6, 2nd is 5, 3rd is 5

Step-by-step explanation:

3x-2=x+10

3x-x=10+2

2x=12

x=12÷2

x=6

x+4=19-2x

x+2x=19-4

3x=15

x=15÷3

x=5

8z-20=z+15

8z-z=15+20

7z=35

z=35÷7

z=5

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Answer 2

Answer:

3x-2=x+10

x=6

x+4=19-2x

x=5

8z-20=z+15

z=5

Step-by-step explanation:

3x-2=x+10

+2 on both sides

3x-2(+2)=x+10(+2)  =>  3x=x+12

subtract x on both sides

3x(-x)=x(-x)+12   =>  2x=12

divide 2 on both sides

2x/2=12/2

= x=6

x+4=19-2x

subtract 4 on both sides

x+4(-4)=19(-4)-2x    =>    x=15-2x

add 2x on both sides    

x(+2x)=15-2x(+2x)     =>    3x=15

divide 3 on both sides

3x/3=15/3

= x=5

8z-20=z+15

subtract z on both sides

8z(-z)-20=z(-z)+15    =>  7z-20=15

add 20 on both sides

7z-20(+20)=15(+20)

7z=35

divide 7 on both sides

7z/7=35/7

= z=5