I need help with these three equations
3x - 2 = x + 10
X+4=19-2x
8z - 20 =z +15
2 answers:
Answer:
1 s t answer is 6 , 2 n d is 5 , 3 r d is 5
Step-by-step explanation:
3x-2=x+10
3x-x=10+2
2x=12
x=12÷2
x=6
x+4=19-2x
x+2x=19-4
3x=15
x=15÷3
x=5
8z-20=z+15
8z-z=15+20
7z=35
z=35÷7
z=5
plzz mark me as brainliest
Answer:
3x-2=x+10
x=6
x+4=19-2x
x=5
8z-20=z+15
z=5
Step-by-step explanation:
3x-2=x+10
+2 on both sides
3x-2(+2)=x+10(+2) => 3x=x+12
subtract x on both sides
3x(-x)=x(-x)+12 => 2x=12
divide 2 on both sides
2x/2=12/2
= x=6
x+4=19-2x
subtract 4 on both sides
x+4(-4)=19(-4)-2x => x=15-2x
add 2x on both sides
x(+2x)=15-2x(+2x) => 3x=15
divide 3 on both sides
3x/3=15/3
= x=5
8z-20=z+15
subtract z on both sides
8z(-z)-20=z(-z)+15 => 7z-20=15
add 20 on both sides
7z-20(+20)=15(+20)
7z=35
divide 7 on both sides
7z/7=35/7
= z=5
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