So since angle A is 120, so angles B+C=60 because there are 180 degrees in a triangle. So B:C is 2:1. So angle B is 40 and angle C is 20.
Answer:
I got you.
Step-by-step explanation:
A. >
B. =
C. >
D. <
Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!
The answer 2+(-3) well I just need to add more so don’t pay attention to this
