This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
flip it please
Step-by-step explanation:
d for 1 and a for 2
Its most likely c
hope it helps
Answer:
864 squared meters
Step-by-step explanation:
Set up a proportion. The scale between 270 and 360 should be the same as 648 to the fourth yard.
Answer:
The triangles are congruent by Angle Side Angle congruency statement and the reason is below.
Step-by-step explanation:
Given:
∠ VUW ≅ ∠ XYW
VW ≅ YW
To Prove:
Δ VUW ≅ Δ XYW
Proof:
In Δ VUW and Δ XYW
∠ VUW ≅ ∠ XYW ……….{Given}
VW ≅ YW ............{Given}
∠ VWU ≅ ∠ XWY …………..{Vertically Opposite Angles are equal}
Δ VUW ≅ Δ XYW .….{ By Angle-Side-Angle congruence test}
......Proved
