Answer:
or
(Not sure which one is preferred in your case)
Step-by-step explanation:
<u>Key skills needed: Evaluating expressions</u>
1) We are given:
2) To solve for the x variable, we want to leave the term with "x" by itself.
This means we add 10 to both sides
-->
(Since -10 and +10 cancel out to make 0 or nothing)
3) Then we divide by 5 on both sides to get "x" completely by itself.
----->
4) You can keep it as is so --> ![x = \frac{y + 10}{5}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7By%20%2B%2010%7D%7B5%7D)
or you can divide "y" by 5 and "10" by 5 and get --> ![x = \frac{1}{5} y + 2](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1%7D%7B5%7D%20y%20%2B%202)
(I am not sure which form is preferred one is preferred as the teacher matters)
<em>Hope you understood and have a nice day!!</em>
Answer:
hope it will help u .....
Answer:
Ainsworth (1970) identified three main attachment styles, secure (type B), insecure avoidant (type A) and insecure ambivalent/resistant (type C).
Step-by-step explanation:
For example, Schaffer and Emerson suggested that attachments develop in four stages: asocial stage or pre-attachment (first few weeks), indiscriminate attachment (approximately 6 weeks to 7 months), specific attachment or discriminate attachment (approximately 7-9 months) and multiple attachment (approximately 10
From the function y=x^2-4x+7
to complete the square we proceed as follows:
The vertex form is given by:
y=(x-h)^2+k
where (h,k) is the vertex:
thus from the function we shall have:
y=x^2-4x+7
c=(b/2a)²
c=(4/2)²=4
thus adding an subtracting 4 in the expression:
y=x^2-4x+4-4+7
y=(x-2)^2+3
thus the vertex will be:
(2,3)
The answer is:
<span>D. Minimum at (2, 3)</span>
Answer:
25X5
Step-by-step explanation:
If you follow the PEMDAS rule the first thing you must do is the equation inside the parenthesis.
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction