What is the heaviest alkali metal
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The question is incomplete, here is the complete question:
A student prepares a 0.21 mM aqueous solution of trimethylacetic acid. Calculate the fraction of trimethylacetic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to 3 significant digits.
<u>Answer:</u> The percent of dissociation of trimethylacetic acid is 19.5 %
<u>Explanation:</u>
We are given:
Concentration of trimethylacetic acid = 0.21 mM = 0.00021 M (Conversion factor: 1 mole = 1000 millimoles )
The chemical equation for the dissociation of trimethylacetic acid follows:
<u>Initial:</u> 0.00021
<u>At eqllm:</u> 0.00021-x x x
The expression of for above equation follows:
We know that:
Putting values in above expression, we get:
Neglecting the negative value of 'x' because concentration cannot be negative.
To calculate the fraction of dissociation, we use the equation:
Putting values in above equation, we get:
Hence, the percent of dissociation of trimethylacetic acid is 19.5 %
Explanation:
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