All categories

1 year ago

How many calories of heat are needed to raise the temperature of 33.0 g of diethyl ether from 14.0 ∘C to 25.0 ∘C ?

Chemistry

1 answer:

Xelga [282]1 year ago

3 0

The amount of heat (in calories) needed to raise the temperature is 324.885 calories

<h3>How to determine the temperature change </h3>

We'll begin by obtaining the temperature change. This can be obtained as followed:

Initial temperature (T₁) = 14 °C
Final temperature (T₂) = 25 °C
Change in temperature (ΔT) = ?

ΔT = T₂ - T₁

ΔT = 25 - 14

ΔT = 11 °C

<h3>How to determine the heat (in Calories)</h3>

The amount of heat needed to raise the temperature can bee obtaimedals follow:

Mass (M) = 33 g
Change in temperature (ΔT) = 11 °C
Specific heat capacity (C) of diethyl ether = 0.895 cal/g°C
Heat (Q) =?

Q = MCΔT

Q = 33 × 0.895 × 11

Q = 324.885 calories

Thus, the amount of heat needed is 324.885 calories

Learn more about heat transfer:

brainly.com/question/10286596

#SPJ1

You might be interested in

What are some other molecules in the plasma membrane explain their function.

Cerrena [4.2K]

Answer:..

Explanation:

5 0

3 years ago

Read 2 more answers

For the following reaction, 9.60 grams of butane (C4H10) are allowed to react with 17.0 grams of oxygen gas. butane (C4H10) (g)

dangina [55]

Answer:

14.4 g of $CO_{2}$ can be produced.

Explanation:

Balanced equation: $2C_{4}H_{10}+13O_{2}\rightarrow 8CO_{2}+10H_{2}O$

Molar mass (g/mol)

$C_{4}H_{10}$ 58.12

$O_{2}$ 32

$CO_{2}$ 44.01

So, 9.60 g of $C_{4}H_{10}$ = $\frac{9.60}{58.12}mol=0.165mol$

17.0 g of $O_{2}$ = $\frac{17.0}{32}mol=0.531mol$

According to balanced equation-

2 moles of $C_{4}H_{10}$ produce 8 moles of $CO_{2}$

So, 0.165 moles of $C_{4}H_{10}$ produce $(\frac{8}{2}\times 0.165)mol$ of $CO_{2}$ or 0.660 moles of $CO_{2}$

13 moles of $O_{2}$ produce 8 moles of $CO_{2}$

So, 0.531 moles of $O_{2}$ produce $(\frac{8}{13}\times 0.531)moles$ of $CO_{2}$ or 0.327 moles of $CO_{2}$

As least number of moles of $CO_{2}$ are produced from $O_{2}$ therefore $O_{2}$ is the limiting reagent.

So, maximum amount of $CO_{2}$ that can be formed = 0.327 moles

= $(0.327\times 44.01)g$

= 14.4 g

3 0

3 years ago

Can you explain what happens to resistance when voltage is increased?

Novay_Z [31]

Resistance is directly proportional to voltage so when you increase Voltage resistance will also increase in order to keep the rate of flow of charge (current) constant

Hope this helps!

4 0

3 years ago

What is the term for the lumps that form when an acid is added to milk? suspension precipitate gas colloid

Murrr4er [49]

Precipitate

hope this helped please mark as brainlest please ! have a good day

8 0

4 years ago

Read 2 more answers

How are they related "atom" "molecule"

zhenek [66]

Answer:

mixture of atoms forms molecule

7 0

3 years ago

Read 2 more answers