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pickupchik [31]
3 years ago
15

Someone plz help me :(

Mathematics
2 answers:
just olya [345]3 years ago
7 0

Answer:

B

Step-by-step explanation:

B and E :)

shepuryov [24]3 years ago
5 0

Answer: your answer is b

Step-by-step explanation:

hope this helps brainliest?

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A printer is printing photos, for every 6 photos, the printer takes 2 minutes
patriot [66]
Whats the question? It prints 3 photos a minute.
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3 years ago
Share 264 in the ratio 2:3:1
NikAS [45]

Answer:

88:132:44

Step-by-step explanation:

Divide 264 by 6 (2+3+1) = 44

2*44=88

3*44=132

1*44=44

7 0
3 years ago
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Solve the following quadratic-linear system of equations. y=x^2-x-6 and y=2x-2
Keith_Richards [23]

You can do substitution 2x-2=x^2 -x -6; isolate all terms on one side 0= x^2 -x-2x -6+2; combine like terms x^2 -3x -4=0; factor the quadratic (x-4)(x+1)=0; each term is zero x-4=0 so x=4 and x+1=0 so x=-1. Now, y=2•4-2=6 and y=2•(-1) -2= -4 ; solutions for the system are ( 4,6) and ( -1, -4)

8 0
3 years ago
Read 2 more answers
Use spherical coordinates. evaluate xyz dv e , where e lies between the spheres ρ = 4 and ρ = 6 and above the cone ϕ = π/3.
sergey [27]

Set

x=\rho\cos\theta\sin\varphi

y=\rho\sin\theta\sin\varphi

z=\rho\cos\varphi

so that the volume element is

\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

The integral is then

\displaystyle\iiint_Exyz\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi/3}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=4}^{\rho=6}\rho^5\cos\theta\sin\theta\sin^3\varphi\cos\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\rho

=\displaystyle\left(\int_0^{\pi/3}\sin^3\varphi\cos\varphi\,\mathrm d\varphi\right)\underbrace{\left(\int_0^{2\pi}\cos\theta\sin\theta\,\mathrm d\theta\right)}_0\left(\int_4^6\rho^5\,\mathrm d\rho\right)

and so evaluates to 0.

3 0
3 years ago
Please help!
likoan [24]

Answer: 123

Step-by-step explanation:

5 0
3 years ago
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