Question

What is an equation of the line that passes through the points (4, 4) and (8,1)?

Answer 1

Answer:

Step-by-step explanation:

first find the slope with m= $\frac{y2-y1}{x2-x1}$

M = $\frac{y2-y1}{x2-x1}$ = $\frac{1-4}{8-4}$ = $\frac{-3}{4}$ ← SLOPE

then add in one of the points so I am using (4, 4)

Y = mx+b

4 = $\frac{-3}{4}$(4)+b

4 = -3 + b

add 3 to both sides

7=b

then add those two answers into the y=mx+b formula so it would be

Y=$\frac{-3}{4}$ x + 7