Help pleaseeeee????????????

Sebastian swan laps every day in the community swimming pool. he swam 45 minutes each day, 5 days each week, for 12 weeks. in th

valina [46]

The first thing we must do for this case is find the amount of minutes we have then:
"45 minutes each day, 5 days each week, for 12 weeks":
(45) * (5) * (12) = 2700 minutes.
We consider the following conversion:
1 hour = 60 minutes.
Therefore the number of hours is:
(2700) * (1/60) = 45 hours
Finally the average rate in laps per hour is:
Average = (1800) / (45)
Average = 40 laps / hour
Answer:
his average rate in laps per hour is:
40 laps / hour

7 0

3 years ago

Translate the shape A three squares right and one square up

jonny [76]

To better give a visual, I drew it out instead.

The attachment is the solution.

8 0

2 years ago

Read 2 more answers

Name the angle pair of angles 1 and 2.

AleksandrR [38]

Step-by-step explanation:

angles on a straight line

4 0

3 years ago

A park district has 45 pine trees and 30 oak trees to be planted. They are separating the trees for different areas. They want e

Lady_Fox [76]

Answer:

greatest number of areas that can be created=5

Step-by-step explanation:

given data

Number of pine trees = 45

Number of oak trees = 30

solution

we want area have same number of both trees

so we get here greatest number of area

we find here greatest common factor of 45 and 30

so Prime factorization of 45 and 30 are

45 = 3 × 3 × 5

30 = 2 × 3 × 5

as here GCF = 5

so here greatest number of areas that can be created=5

6 0

3 years ago

Minor surgery on horses under field conditions requires a reliable short-term anesthetic producing good muscle relaxation, minim

andreev551 [17]

Answer:

$p_v =P(t_{74}$

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

Step-by-step explanation:

Data given and notation

$\bar X=18.81$ represent the average lateral recumbency for the sample

$s=8.4$ represent the sample standard deviation

$n=75$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a left tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu \geq 20$

Alternative hypothesis : $\mu < 20$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227$

The degrees of freedom are given by:

$df=n-1=75-1=74$

Give the appropriate conclusion for the test

Since is a one side left tailed test the p value would be:

$p_v =P(t_{74}$

Conclusion

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

3 0

3 years ago