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Zepler [3.9K]
3 years ago
9

4.2(5.1x+6.8) Simplify the expression

Mathematics
1 answer:
vovikov84 [41]3 years ago
6 0

Answer:

21.42x+28.56

Step-by-step explanation:

Expand: 4.2×5.1×x+4.2×6.8

4.2×5.1×x  to (21.42)x

Simplify: 21.42x+4.2×6.8

4.2×6.8 = 28.5628.56

21.42x+28.56

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Answer:

x = - \frac{7}{4}

Step-by-step explanation:

Given

20x + 12 = 4x - 16 ( subtract 4x from both sides )

16x + 12 = - 16 ( subtract 12 from both sides )

16x = - 28 ( divide both sides by 16 )

x = \frac{-28}{16} = - \frac{7}{4} [ = - 1.75 ]

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Step-by-step explanation:

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Two positive, consecutive, odd integers have a product of 143. what is the equation and the greater integer?
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5 0
3 years ago
The angle of elevation to the top of a water tower from point A on the ground is 19.9°. From point B, 50.0 feet closer to the to
zepelin [54]

Answer:

Answer in terms of a trigonometric function :

h = \frac{20tan(19.9)}{0.4-tan(19.9)}

Answer in figures

h = 190.5 feet

Step-by-step explanation:

Consider the sketch attached below to better understand the problem.

Let x be the distance between point B and the base of the water tower.

tan (19.9)=\frac{h}{50+x} ---------------equation 1\\

tan (21.8)=\frac{h}{x}----------------equation 2

From equation 2,

x =\frac{h}{tan21.8}=\frac{h}{0.4}

substituting the value of x into equation 1, we get

tan (19.9)=\frac{h}{50+(\frac{h}{0.4} )}

tan 19.9=h\times \frac{0.4}{20+h}

cross multiplying,

20\times tan(19.9) +htan(19.9)=0.4h

20tan(19.9)= h(0.4-tan(19.9))

h= \frac{20tan (19.9)}{0.4-tan (19.9)}

The height of the tower is h= \frac{20tan (19.9)}{0.4-tan (19.9)} in terms of the trig function "Tan"

The equation can simply be evaluated to get the answer in figures since the angles are given in the question

5 0
3 years ago
ਕind me<br>When x = 4 and y = 3, find the value of:<br>a) 2x + 7y - 10​
Andre45 [30]

Answer:

19

Step-by-step explanation:

by replacing x and y with their given values ,

we get :-

=》2x + 7y - 10

=》(2 × 4) + (7 × 3) - 10

=》8 + 21 - 10

=》29 - 10

=》19

5 0
3 years ago
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