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Nataly [62]
3 years ago
11

Jessa bought her home for $125,000 in 2010 Property values have increased 15% every year since she has owned the home. Which of

the following equations can be used to represent the price of the home x years after 2010?
y = 125,000(1 15)
y = 125 000(125)
y = 125,000(085)
y = 125.000(075)
Mathematics
2 answers:
kramer3 years ago
3 0

Answer:

y= 125,000 (1.15x)

Step-by-step explanation:

timurjin [86]3 years ago
3 0

Answer:

A. y=125,000\cdot (1.15)^x

Step-by-step explanation:

We have been given that Jessa bought her home for $125,000 in 2010 Property values have increased 15% every year since she has owned the home.

We can see that increase in value of house is not constant, so the value of house in increasing exponentially.

We know that an exponential function is in form y=a\cdot b^x, where,

a = Initial value,

b = For growth b is in form (1+r), where r represents growth rate in decimal form.

r=\frac{15}{100}=0.15

y=125,000\cdot (1+0.15)^x

y=125,000\cdot (1.15)^x

Therefore, the equation y=125,000\cdot (1.15)^x represents the price of the home x years after 2010.

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Answer:

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=652.6 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size  

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=50-1=49

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that t_{\alpha/2}=2.01

Now we have everything in order to replace into formula (1):

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

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