First, assume the order of the given reaction is n, then the rate of reaction i.e. ![\frac{dx}{dt}=k\times[A]^{n}](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%3Dk%5Ctimes%5BA%5D%5E%7Bn%7D)
where, dx is change in concentration of A in small time interval dt and k is rate constant.
According to units of rate constant, the reaction is of second order.
![\frac{1}{[A]_{t}}-\frac{1}{[A]_{o}} = kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D_%7Bt%7D%7D-%5Cfrac%7B1%7D%7B%5BA%5D_%7Bo%7D%7D%20%3D%20kt)
(second order formula)
Put the values,
t= 587.9 s
Hence, time taken is 587.9 s
B............................
To keep burning, fires require oxygen. Carbon dioxide is used in certain fire extinguishers to put out flames. Explanation: Because magnesium is higher on the reactivity scale than carbon, it is more reactive and eliminates oxygen from carbon dioxide (to give carbon and magnesium oxide).
Answer: the formula is NO
Answer:
380.5g/mol
Explanation:
The molar mass of a compound can be obtained by adding the molar masses of the elements present in the compound.
The molar mass of Cu3(PO4)2 can be obtained as follow:
Molar Mass of Cu = 63.5g/mol
Molar Mass of P = 31g/mol
Molar Mass of O = 16g/mol
The molar mass of Cu3(PO4)2 = (63.5x3) + 2[31 + (16x4)] = 190.5 + 2[31 + 64] = 190.5 + 2[95] = 190.5 + 190 = 380.5g/mol
