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Dennis_Churaev [7]
3 years ago
13

A hygroscopic compound readily absorbs water from the air. This water can be removed by gently heating the compound. 5.24 g of a

hygroscopic compound was heated to remove the absorbed water. After heating the dry compound had a mass of 4.16 g. What was the mass percent of water in the original compound?
Chemistry
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

This means 20.6% of the original hygrocopic compound is water

Explanation:

<u>Step 1:</u> Given data

A hygroscopic compound weighs 5.24 grams

To remove the absorbed water the compound is heated.

After the heating process, the compound weighs 4.16 grams

<u>Step 2:</u> Calculate the mass of the water

The total mass of the hygroscopic compound = mass of water + mass of dry compound

The mass of water = The total mass of the hygroscopic compound - mass of dry compound

The mass of water = 5.24 grams - 4.16 grams = 1.08 grams

<u>Step 3: </u>Calculate the mass percent of water in the original compound

1.08g / 5.24g *100% = 20.6%

<u>Step 4: </u>To control this we can calculate the mass percent of the dry compound

4.16g / 5.24g *100 % = 79.4%

20.6% + 79.4% = 100%

This means 20.6% of the original hygrocopic compound is water

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