Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.
1 answer:
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In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.
Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.
For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.
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Answer:
The answer is "10.84 g".
Explanation:
The formula for calculating the number for moles:
In the given acid nitric:
Owing to the nitric acid mass =
Nitric acid molar weight
If they put values above the formula, they receive:
In the given chemical equation:
In this reaction, 2 mols of nitric acid are produced by 1 mole of water.
So, 1.204 moles of nitric acid will be produced:
We are now using Equation 1 in determining the quantity of water:
Water moles
Water weight molar