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Katena32 [7]
3 years ago
9

Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.

02 g/mL. Only enter the numerical value with 3 significant figures in the answer box below. Do NOT type in the unit (m).
Chemistry
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

2.03

Explanation:

Let's <u>assume we have 1 L of the solution</u>:

  • There would be 2.07 ethylene glycol moles.
  • The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.

With that information we can <u>calculate the molality</u>:

  • molality = moles of solute / kg of solvent
  • molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

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storchak [24]

pH of 0.048 M HClO is 4.35.

<u>Explanation:</u>

HClO is a weak acid and it is dissociated as,

HClO ⇄ H⁺ + ClO⁻

We can write the equilibrium expression as,

Ka = $\frac{[H^{+}] [ClO^{-}]  }{[HClO]}

Ka = 4.0 × 10⁻⁸ M

4.0 × 10⁻⁸ M = $\frac{x \times x }{0.048}

Now we can find x by rewriting the equation as,

x² =  4.0 × 10⁻⁸ × 0.048

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Taking sqrt on both sides, we will get,

x = [H⁺] = 4.38 × 10⁻⁵

pH = -log₁₀[H⁺]

     = - log₁₀[ 4.38 × 10⁻⁵]

   = 4.35

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1

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What is the percent yield if 3.47 g of copper is produced when 1.87 g of aluminium is reacted with excess of copper (II) sulfato
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Give 3 Examples of where potential energy was converted to knlinetic energy:

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The ball is still, that is potential energy. Then the ball is moving, the is kinetic energy

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Hope this helps

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