Question

Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.02 g/mL. Only enter the numerical value with 3 significant figures in the answer box below. Do NOT type in the unit (m).

Answer 1

Answer:

2.03

Explanation:

Let's assume we have 1 L of the solution:

• There would be 2.07 ethylene glycol moles.

• The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.

With that information we can calculate the molality:

• molality = moles of solute / kg of solvent

• molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.