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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
John and Pam are paid $8.5 for each hour worked. John's share of the money is $29.75.
Step-by-step explanation:
Let x = the hourly salary. John worked for 3.5 hrs, and Pam for two. We can represent this using the equation:
3.5x + 2x = 46.75, where the coefficients equals the amount of hours.
Let's solve for x!
5.5x=46.75
x = 46.75/5.5 = 17/2 = 8.5
John and Pam are paid 8.5 dollars per each hour worked.
To figure out John's share of the money, we will multiply the wage by the hours he worked.
8.5 x 3.5 = 29.75
Answer:
umm I think it 186
Step-by-step explanation:
You would round 1.049 to 1.05.
