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Arturiano [62]
3 years ago
12

What are the steps used to transform the general form of the equation of a circle to standard form

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0

Answer:

Step-by-step explanation:

Convert the equation of a circle in general form shown below into standard form. Find the center and radius of the circle. Group the x 's and y 's together. Consider the x2 and x terms only. Complete the square on these terms. Replace the x2 and x terms with a squared bracket.

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Answer:

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Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A box is in the shape of a right rectangular prism. The base of the box has an area of 15 square inches. The height of the box i
nata0808 [166]
The answer is 180cubic2 (square)
7 0
2 years ago
Write an R-program to sample n = 1000 values from the BlackwellMacQueen Pólya urn for µ = αH where H is a non-atomic bivariate d
earnstyle [38]

poyo and churizzo uiouigyuftydfyitfogpghlhbl

8 0
2 years ago
What's it take for someone to help me with this problem ;-;
Colt1911 [192]

Answer:

x = 8 degrees

Step-by-step explanation:

The thing in red says "vertically opposite"

3 0
3 years ago
What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = StartFraction neg
Harman [31]

Answer:

x=\frac{-5(+/-)\sqrt{5}} {2}

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

f(x)=x^{2} +5x+5  

equate the function to zero

x^{2} +5x+5=0  

so

a=1\\b=5\\c=5

substitute in the formula

x=\frac{-5(+/-)\sqrt{5^{2}-4(1)(5)}} {2(1)}

x=\frac{-5(+/-)\sqrt{5}} {2}

therefore

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

6 0
3 years ago
Read 2 more answers
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