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3 years ago

Determine whether the lines are parallel. Use slope to explain your answer. Use the graph shown below

Mathematics

2 answers:

Westkost [7]3 years ago

7 0

Answer:

non of the obove

Step-by-step explanation:

vivado [14]3 years ago

4 0

The slope of the red line is 1 and the slope of the blue line is also 1. you figure it out by finding the rise/run. so start at a point and go up and over to find the slope. for both it is 1/1, up one over one. they are parallel.

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Una empresa embotelladora de gaseosas lanzará su propia bebida "Delicia" de un litro a un costo variable de S/ 2.50 por unidad,

KIM [24]

Por la ecuación de utilidad, necesitamos una producción de 7,667 botellas de un litro de capacidad para obtener un total de utilidades de S/ 30.000.

<h3>¿Cómo determinar las utilidades por la venta de bebidas gaseosas?</h3>

Las utilidades (U') se obtienen de sustraer los costes de producción (Cp) a las utilidades <em>netas</em> (U). Los costes de producción (Cp) son la suma de costes <em>variables</em> (C') y costes <em>fijos </em>(C). y la utilidades <em>netas</em> proceden de la venta de botellas. En consecuencia, tenemos la siguiente expresión:

U' = U - Cp

U' = U - C' - C

A continuación, desarrollamos y resolvemos la ecuación resultante:

30000 = 4.50 · x - 2.50 · x - 18500

1.50 · x = 11500

x = 7667

Por la ecuación de utilidad, necesitamos una producción de 7,667 botellas de un litro de capacidad para obtener un total de utilidades de S/ 30.000.

Para saber sobre utilidades: brainly.com/question/16933668

#SPJ1

6 0

2 years ago

Please help me ( show ur work it’s multiple choice ):)

GaryK [48]

B=29.4 !!!!!!!! this how i do it

7 0

2 years ago

Elmer has a collection of 300 fossils. Of those, 21% are fossilized snail shells. How many fossilized snail shells does Elmer ha

kakasveta [241]

Use the percent proportion

21 x
—— = ——
100 300

to solve :
21 x 300 = 6300
6300 ÷ 100 = 63

Answer = 63 of Elmer’s shells are fossilized snail shells :)

4 0

3 years ago

What is the equation of the line passing through points (1,1) and (3,-5)

seraphim [82]

Answer:

m=-3

Step-by-step explanation:

5 0

2 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago