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vova2212 [387]
3 years ago
9

What is the lowest value of the range of the function shown on the graph?

Mathematics
2 answers:
insens350 [35]3 years ago
5 0
The complete question in the attached figure

we know that
the range is the y-value  of the function
so
the lowest y-value on this graph is y = -2.

the answer is
y=-2

garri49 [273]3 years ago
3 0

Answer:

the answer is  y=-2

Step-by-step explanation:


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Which equation has exactly one solution?
ycow [4]
Your answer would be 4x-7=-3(3+4x) because it only has one solution which is x= -1/8
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3 years ago
Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that
Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is P(x_1 + x_2 \ge 2 )= 0.5940

Step-by-step explanation:

From the question we are told that

     The rate at which fire breaks out every 10 years is  \lambda  =  1

  Generally the probability distribution function for Poisson distribution is mathematically represented as

               P(x) =  \frac{\lambda^x}{ k! } * e^{-\lambda}

Here x represent the number of state which is  2 i.e x_1 \ \ and \ \ x_2

Generally  the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

          P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 + x_2 \le 1 )

=>        P(x_1 + x_2 \ge 2 ) =  1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]

=>        P(x_1 + x_2 \ge 2 ) =  1 - [ P(x_1  = 0 ,  x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]

=>  P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)

=>    P(x_1 + x_2 \ge 2 ) =  1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}

=>   P(x_1 + x_2 \ge 2 )= 1- [[0.3678  * 0.3679] + [0.3678  * 0.3679] + [0.3678  * 0.3679]  ]

P(x_1 + x_2 \ge 2 )= 0.5940

               

3 0
2 years ago
Can some on help me on this question?
mario62 [17]

Answer:

x=10 and x-7 is the answer

Step-by-step explanation:

a)2x-7=13

2x=13+7

2x=20

x=20/2

x=10

b)3x+4=25

3x=25-4

3x=21

x=21/3

x=7

i hope it will help you

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2 years ago
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Mars2501 [29]

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Rate= R(4/100=0.04)

Time= T(5)

SI=P•R•T

SI=97x0.04x5

SI=19.4

Interest earned = $19.4

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2.5 what just use the formula pi•(4/3r•r)
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