Answer:
Dimensions of the container:
x = 3 m
y = 6 m
h = 1.1 m
C(min) = 270 $
Step-by-step explanation:
Volume of storage container
V = 20 m³
Let "y" be the length and "x" the width then y = 2*x
V = x*y*h ⇒ V = 2*x²*h ⇒ 20 = 2*x²+h ⇒ h = 10/ x²
Costs:
Total cost = cost of base ( 5*2*x² ) + cost of side with base x ( 2*9*x*h) +
cost of side witn base y =2x (2*9*2x*h)
C(t) = 10*x² + 18*x*h + 36*x*h
C(x) = 10x² + 54*x*10/x² ⇒ C(x) 10*x² + 540 /x
Taking derivatives on both sides of the equation we get:
C´(x) = 20*x - 540/x²
C´(x) = 0 ⇒ 20*x - 540/x² = 0 ⇒ 2x - 54/x² = 0
2x³ - 54 = 0
x³ = 27 x = 3 m
Then y = 2*x ⇒ y = 2*3 y = 6 and h = 10 / x² h = 1.1 m
And the minimum cost is
C (min) = 10*x² + 540/x ⇒ C (min) = 90 + 180
C(min) = 270 $
Answer:
Option (A).
Step-by-step explanation:
Given question is incomplete; find the complete question with the attachment.
In the triangle NRL,
Points P, S and M are the midpoints of the sides NR, RL and LN respectively.
Sides SM = (3x - 4), NR = (9x - 20)
By the theorem of midpoints in a triangle,
SM = 
(3x - 4) = 
6x - 8 = 9x - 20
9x - 6x = 20 - 8
3x = 12
x = 4
Therefore, Option (A) will be the answer.
Answer:
Answer is 105 in^2
Step-by-step explanation: Area of rectangle= length X breadth
= 8X12
=96in^ 2
Area of triangle= 1/2 X base X height
= 1/2 X 3 X 6
= 9 in^2
Area of irregular pentagon = area of triangle + area of rectangle
= 96+9
=105 in ^2
Answer:
X = 64
Step-by-step explanation:
Comparing the two triangle put the right angle into consideration.
(17 + X)/(X + 8) = (X + 8)/X
Cross multiplying
X(17 + X) = (X + 8)(X + 8)
17X + X^2 = X^2 + 8X + 8X + 64
Collecting like terms
X^2 - X^2 + 17X - 8X - 8X = 64
X = 64
Answer:
Below is the graph which answers your question. Hopefully this helps :)
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