I need help solving this proportion!! 3/x-1 = 2/x+4

1 answer:

3 0

1. Move 2/x to the left side of proportion by changing sign before it:
3/x - 1 - 2/x = 4

2. Move 1 to the right side of proportion and change it's sign as well:
3/x - 2/x = 4 + 1

3. Sum numerators in the left side of proportion since they have common denominator (x) abd also sum the numbers in the right side too:
(3-2)/x = 5

4. Calculate numerator in the left side of proportion:
1/x = 5

5. Move 1 to the right side of proportion by dividing that side by it:
x = 1/5

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Can someone solve this with steps cause idk how to solve the radicals

IceJOKER [234]

$\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
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\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
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\\\\\\
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to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.

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antiseptic1488 [7]

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Dmitriy789 [7]

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