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anastassius [24]
3 years ago
14

How do you find the height and area of this triangle

Mathematics
1 answer:
Doss [256]3 years ago
8 0
Because the triangle is an equilateral triangle, you know that all of the angles are equal to 60°. That means that you can use trigonometry to find the height, which would be sin(60) × 20 = 17.32.

Again, because it is an equilateral triangle, all sides are equal as well, meaning that the base is also 20cm. To find the area of the triangle, we must do (20 × 17.32)/2 = 173.2cm^2, which is the area.

I hope this helps!
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Veronica bought 20 bags of candy for a school dance the first 5 bags cost $1.79 each the rest of the bags cost $1.19 each how mu
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3 years ago
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Please see the figure. We'll first work out half the area of the rounded triangle, half the unshaded part, then double it, then subtract it from the big square.

Half the area is the circular sector PTQ (with center P, arc TQ) minus the right triangle PUT.

A/2 = area(sector PTQ) - area(triangle PUT)

The triangle is half of equilateral triangle PQT, so a 30/60/90 right triangle so we know the sides are in ratio 1:√3:2 so

TU = (7/2)√3

area(PUT) = (1/2) (7/2)(7/2)√3 = (49/8)√3

area(sector PTQ) = (angle TQP / 360°) πr^2

We know angle TQP is 60° because TQP is equilateral.  r=7.

area(sector PTQ) = (60°/360°) π (7²) = 49π/6

Putting it together,

A/2 = area(sector PTQ) - area(triangle PUT)

A = 2(49π/6 -  (49/8)√3)

A = 49(π/3 - √3/4) square cm

I hate ruining a nice exact answer with an approximation, but they seem to be asking.

A ≈ 30.095057615914535

Check:

I'm not sure how to check it.  I'd estimate it's about 25% bigger than equilateral triangle PQT with area (√3/4)7² ≈ 21.2, so around 27. 30 seems reasonable.

Now the real area we seek is the big square PQRS minus A, so

area = 7² - 30.095057615914535 = 18.904942384086 sq cm

They want square meters for some reason; we scale by (1/100)²

Answer: 0.00189 square meters

7 0
3 years ago
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