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liubo4ka [24]
3 years ago
5

PLSSSS HELPPP MEEEEEE

Mathematics
1 answer:
labwork [276]3 years ago
5 0
Circumference of the smaller circle, using C = \pi d, is approximately equal to 18.85 (I used the high floating point precision approximation of pi my calculator has in memory, then rounded to 2 decimal points.)

Using the formula S = 0.2L, which in English says "the smaller circle's circumference is equal to 20% of the larger circle's", we can substitute the known value S: 18.85 = 0.2L and solve for L: \frac{18.5}{0.2} = L, L = 92.5.

So the larger circle has a circumference approximately equal to 92.5 units.  

 
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A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)
Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}

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2 years ago
Can someone help me please
ki77a [65]
<span>x = -2.375 Hopefully that helps :)</span>
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