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2 years ago

11

10 dictionare si 2 truse de stiinte costa 550 lei 10 dictionare si 5 truse de stiinte costa 1150 lei cat costa un dictionar ? ca

t costa o trusa de atiinte

1 answer:

astra-53 [7]2 years ago

3 0

Ok I can’t tell what your saying because it’s not fluent

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Can u answer number 10?

KonstantinChe [14]

5.7(0.59)= B
2.8(1.99)= A

8 0

2 years ago

(-3*10^9)(1.27*10^-12) in scientific notation

katen-ka-za [31]

It would be = -3.81 * 10^-3

7 0

3 years ago

A hypothesis test is to be performed for a population proportion. For the given sample data and null hypothesis, compute the val

liberstina [14]

Answer:

The correct option is a

Step-by-step explanation:

From the question we are told that

The sample size is n = 415

The sample proportion is $\r p = 0.49$

Now

The null hypothesis is $H_o : p = 0.3$

The alternative hypothesis is $H_a : p \ne 0.3$

The test statistics is mathematically evaluated as

$t = \frac{\r p - p }{ \frac{\sqrt{ p (1- p )} }{n} }$

substituting values

$t = \frac{0.49 - 0.3 }{ \sqrt{ \frac{0.3 (1- 0.3 ) }{415} }}$

$t = 8.446$

8 0

3 years ago

What is the scale factor of the dilation? Help please

DaniilM [7]

Imagine A'V' is part of the dilated figure, and AV is part of the original figure.

A'V' = 3.2

AV = 3.2 + 4.8 = 8

A'V'/AV = 3.2/8 = 2/5

Answer: First choice, 2/5.

4 0

3 years ago

Given the following data, find the weight that represents the 53rd percentile.

Volgvan

Answer:

Step-by-step explanation:

Rearranging the weights in ascending order, it becomes

5.4, 5.7, 5.7, 5.8, 6.0, 6.6, 7.1, 7.1, 7.5, 7.5, 8.1, 8.7, 9.3, 9.4, 9.4

The formula for determining the percentile is expressed as

n = (P/100)N

Where

n represents the value of the given percentile

P represents the given percentile

N represents the number of items(weights)

From the information given, the number of items, n is 15

P = 53

Therefore,

n = (53/100) × 15

n = 7.95

n = 8

Therefore, the weight that represents the 53rd percentile is the 8th value. It becomes 7.1

53rd percentile is 7.1

3 0

2 years ago