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Tamiku [17]
2 years ago
10

3x+13y=-111 6x+15y=-123 solve the following system of equations using any method

Mathematics
1 answer:
GenaCL600 [577]2 years ago
3 0
Multiply the first equation by two to get:

6x + 26y = -222

Subtract the equations from one another:

6x + 26y = -222
Subtract 6x + 15y = -123

This gives you:

11y = -99
So y = -9

Sub y = -9 into

3x + 13(-9) = -111
3x - 117 = -111
3x = 6
X = 2
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olchik [2.2K]

Answer:

12 boys

Step-by-step explanation:

From the above question:

Number of boys = 3

Number of girls = 2

Boys: Girls

3:2

Let :

a = boys

b = girls

Hence, a : b = 3 : 2

a/b = 3/2  

Cross Multiply

2a = 3b .......... Equation 1

a = 3b/2

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Hence,

a: b + 4 = 3 : 3

a/b + 4 = 3/3

Cross Multiply

3a = 3(b + 4)

3a = 3b + 12 ........ Equation (2)

From Equation 1: a = 3b/2

Substitute 3b/2 for a in Equation 2 we have:

3a = 3b + 12 .........Equation 2

3(3b/2) = 3b + 12

9b/2 = 3b + 12

Cross Multiply

9b = 2(3b + 12)

9b= 6b + 24

9b - 6b = 24

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b = 8

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a = 3b/2

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a = 24/2

a = 12

Therefore, the number of boys in the class is 12

7 0
2 years ago
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