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ziro4ka [17]
3 years ago
8

Write .233333 as a fraction

Mathematics
1 answer:
denis-greek [22]3 years ago
6 0
. 233333 as a fraction equals 233333/1000000 is your answer
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Given, OA = OV, what congruency statements can
GuDViN [60]

Given , ⊙A ≅ ⊙V

To find:

What congruency statements can you make? Check all that apply.

BC ≅ ZY

∠ DAB ≅ ∠ ZVX

BE ≅ ZX

Solution:

Consider the attached figure while going through the following steps.

If two circles are congruent, then their corresponding chords are also congruent along with the congruent intercepted arcs.

⇒ BC ≅ ZY

and

⇒ BE ≅ ZX

4 0
2 years ago
Answer please.. Thank you in advance
sergeinik [125]
Picture is in correct
3 0
3 years ago
Prove the following
fomenos

Answer:

Step-by-step explanation:

\large\underline{\sf{Solution-}}

<h2 /><h2><u>Consider</u></h2>

\rm \: \cos \bigg( \dfrac{3\pi}{2} + x \bigg) \cos \: (2\pi + x) \bigg \{ \cot \bigg( \dfrac{3\pi}{2} - x \bigg) + cot(2\pi + x) \bigg \}cos(23π+x)cos(2π+x)

<h2><u>W</u><u>e</u><u> </u><u>K</u><u>n</u><u>o</u><u>w</u><u>,</u></h2>

\rm \: \cos \bigg( \dfrac{3\pi}{2} + x \bigg) = sinx

\rm \: {cos \: (2\pi + x) }

\rm \: \cot \bigg( \dfrac{3\pi}{2} - x \bigg) \: = \: tanx

\rm \: cot(2\pi + x) \: = \: cotx

So, on substituting all these values, we get

\rm \: = \: sinx \: cosx \: (tanx \: + \: cotx)

\rm \: = \: sinx \: cosx \: \bigg(\dfrac{sinx}{cosx} + \dfrac{cosx}{sinx}

\rm \: = \: sinx \: cosx \: \bigg(\dfrac{ {sin}^{2}x + {cos}^{2}x}{cosx \: sinx}

\rm \: = \: 1=1

<h2>Hence,</h2>

\boxed{\tt{ \cos \bigg( \frac{3\pi}{2} + x \bigg) \cos \: (2\pi + x) \bigg \{ \cot \bigg( \frac{3\pi}{2} - x \bigg) + cot(2\pi + x) \bigg \} = 1}}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h2>ADDITIONAL INFORMATION :-</h2>

Sign of Trigonometric ratios in Quadrants

  • sin (90°-θ)  =  cos θ
  • cos (90°-θ)  =  sin θ
  • tan (90°-θ)  =  cot θ
  • csc (90°-θ)  =  sec θ
  • sec (90°-θ)  =  csc θ
  • cot (90°-θ)  =  tan θ
  • sin (90°+θ)  =  cos θ
  • cos (90°+θ)  =  -sin θ
  • tan (90°+θ)  =  -cot θ
  • csc (90°+θ)  =  sec θ
  • sec (90°+θ)  =  -csc θ
  • cot (90°+θ)  =  -tan θ
  • sin (180°-θ)  =  sin θ
  • cos (180°-θ)  =  -cos θ
  • tan (180°-θ)  =  -tan θ
  • csc (180°-θ)  =  csc θ
  • sec (180°-θ)  =  -sec θ
  • cot (180°-θ)  =  -cot θ
  • sin (180°+θ)  =  -sin θ
  • cos (180°+θ)  =  -cos θ
  • tan (180°+θ)  =  tan θ
  • csc (180°+θ)  =  -csc θ
  • sec (180°+θ)  =  -sec θ
  • cot (180°+θ)  =  cot θ
  • sin (270°-θ)  =  -cos θ
  • cos (270°-θ)  =  -sin θ
  • tan (270°-θ)  =  cot θ
  • csc (270°-θ)  =  -sec θ
  • sec (270°-θ)  =  -csc θ
  • cot (270°-θ)  =  tan θ
  • sin (270°+θ)  =  -cos θ
  • cos (270°+θ)  =  sin θ
  • tan (270°+θ)  =  -cot θ
  • csc (270°+θ)  =  -sec θ
  • sec (270°+θ)  =  cos θ
  • cot (270°+θ)  =  -tan θ
7 0
3 years ago
Read 2 more answers
write the equation for the nth term of the sequence and then find the value of the 24th term: 4, 13, 22, 31, ...
julia-pushkina [17]

Answer :

nth term

an = a1 + (n-1) d

an = 4 + (9-1) 9

an = 4 + (8)9

an = 4 + 72

an = 82

24th term

an = 4 + (24-1) 9

an = 4 + (23) 9

an = 4 + 207

an = 211 is the answer

Hope it helped

4 0
3 years ago
A mistake was made in mixing the lemonade—<br> PLEASE HELP!!
beks73 [17]

Answer:

Part A:

4 + x = y

0.5*4 + 1*x = 0.7*y

x = 8/3\ quarts\ of\ 100\%\ solution

y = 20/3\ quarts\ of\ 70\%\ solution

Part B:

x + y = 10

2x + 3y = 23

x = 7 and y = 3

Step-by-step explanation:

Part A:

The inicial concentration of the lemonade is 50%, and the volume is 4 quarts, and we will add x quarts of a lemonade with a concentration of 100%, so the total volume will be y, and the concentration will be 0.7, so we have that:

4 + x = y

0.5*4 + 1*x = 0.7*y

Using the value of y from the first equation in the second one, we have:

2 + x = 0.7*(4 + x)

2 + x = 2.8 + 0.7x

0.3x = 0.8

x = 8/3\ quarts

y = 4 + 8/3 = 20/3\ quarts

Part B:

If he shoots a total of ten targets, we can write the equation:

x + y = 10

Each stationary target is 2 points, and each moving target is 3 points, so if the total points is 23, we have:

2x + 3y = 23

If we subtract the second equation by two times the first one, we have:

2x + 3y - 2*(x + y) = 23 - 2*10

2x + 3y - 2x - 2y = 23 - 20

y = 3

x + 3 = 10 ⇒ x = 7

4 0
3 years ago
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