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Irina18 [472]
3 years ago
6

What is 7+4x-9=-6? i need help asapppp

Mathematics
1 answer:
zhenek [66]3 years ago
8 0
The answer is x = -1
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How much paper will it take to make each tree including the bottom??
Nataly [62]

The bottom is a square with a side length of 2 ft.

The area of a square is Area = S^2 = 2^2 = 4 square ft. Bottom)

The area of one side ( triangle) = 1/2 x base x height = 1/2 x 2 x 4 = 4 square ft.

There are 4 triangles: 4 x 4 sq. ft. = 16 sq.ft. ( four sides)

Total area = four sides + bottom =  16 + 4 = 20 feet^2

7 0
4 years ago
HELP I HAVE TO FINISH THIS FAST
Usimov [2.4K]

Answer:

13 minus 3x cubed

Step-by-step explanation:

6 0
3 years ago
Let SSS represent the number of sunflower plants and LLL represent the number of lily plants Ezra's water supply can water.
Fantom [35]

Answer:

Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.

Step-by-step explanation:

Given the inequality function

0.7S+0.5L≤11 where S represent the number of sunflower plants and L represent the number of lily plants Ezra's water supply can water, if Ezra waters 10 lily plants, then we can calculate the maximum amount of sunflower plant that he can water with the remaining amount of water by simply substituting L = 10 into the inequality function as shown;

0.7S+0.5L≤11

0.7S+0.5(10)≤11

0.7S+5≤11

Taking 5 to the other side:

0.7S≤11-5

0.7S≤6

S≤6/0.7

S≤8.57

This shows that Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.

3 0
4 years ago
Please help?!’ answerr
Ugo [173]

Answer:

The choice Draw 2

Step-by-step explanation:

3(8 - 4x) < 6(x - 5) \\ 24 - 12x < 6x - 30 \\  24- 12x + 12x < 6x + 12x - 30 \\ 24 < 18x - 30 \\ 24 + 30 < 18x - 30 + 30 \\ 54 < 18x \\ 54 \div 18 < 18x \div 18 \\ 3 < x \\ x > 3

I hope I helped you^_^

6 0
3 years ago
(101)² solve it using identities​
almond37 [142]

Answer:

10201

Step-by-step explanation:

=(101)²

=(100+1)²

={100²+2(100)(1)+1²} [(a+b)²=a²+2ab+b²]

=10000+200+1

=10201

7 0
3 years ago
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