<span>erry starts rowing at 2 pm from the west end of the lake, and Tao starts rowing from the east end of the lake at 2:05 pm.
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Terry DATA:
rate = 60 meter/min ; time = x min ; distance = r*t = 60x meters
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Tao DATA:
rate = 40 meter/min ; time = x-5 min ; distance = r*t = 40(x-5) meters
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If they always row directly towards each other at what time will the two meet?
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Equation:
dist + dist = 2000 meters
60x + 40(x-5) = 2000
20x = 1800
x = 90 minutes
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Question 1: 6 3/4 so option b
9,11,13,20
20 -9 = 11
Range: 11 so its not 17
11 + 13 = 24
24/2 = 12
Median: 12 so its not 10
9+ 11 + 13 + 20 = 53
53/4= 13.25
Mean: 13.25 so its not 12
IQR: 6.5 so its not 7 or 12
Radius = √(7-(-1))² + (8-(-7))² = √8²+15² = √289 = 17
Let the point be (-15,y)
(-15-(-7))² + (y-(-1))² = 17²
⇒ -8² + (y+1)² = 17²
⇒ 64 + (y+1)² = 289
⇒ (y+1)² = 289 - 64 = 225
⇒ y+1 = +15 or -15
⇒ y = +15-1 or -15-1
⇒ y = 14 or -16
T<span>h</span>us, the point can be either (-15,14) or (-15,-16)
Answer:
it will take them 3.6 hours if their speed is increased
Step-by-step explanation:
First of all, we will need to find the total distance the Geradi family will be travelling. This is a better way to start, as the distance is constant regardless of their change in velocity.
Distance travelled = speed of travel X time taken = 45 X 4 = 180 miles per hour.
If the Geradi family increases their speed to 50 miles per hour, their new time will be got by dividing the total distance travelled by this new speed.
New travel time = 180 miles / 50 miles per hour = 3.6 hours
