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3 years ago

10

Express the product of (6-2i)(-4+3i) in a+bi form

1 answer:

Dafna1 [17]3 years ago

8 0

Multiply through the parentheses:
-24 + 18i + 8i + 6
18 + 26i

18 + 26i is the answer

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nina bounces on the trampoline in gee backyard. if the circumference of the trampoline is 37.68 feet what is the approximate are

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3 years ago

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What is 9% converted to a fraction

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9/100

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2 years ago

a line passes through the point -2 and five and has a slope of 2/3 points A(x,3) and B(-2,y)lie on the line

olasank [31]

A and B lie on the line, yes, but what specifically are you supposed to do? Looks like your problem statement was cut off before you'd finished typing it in.

You say your line passes thru (-2,5) and has a slope of 2/3? Then, using the point-slope formula,

y-5 = (2/3)(x+2) This is the general equation for your line.

Now let's play around with B(-2,y). Suppose we subst. the x-coordinate of B, which is -2, into the equation y-5 = (2/3)(x+2); we get y-5 = (2/3)(-2+2) = 0. This tells us that y must be 5. But we already knew that!!

So, please review the original problems with its instructions and this discussion and tell me what you need to know from this point on.

7 0

3 years ago

Ignore the stuff around it ,could someone explain me this?

Ierofanga [76]

Answer:

The lines blue and green are perpendicular

Step-by-step explanation:

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is -1)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope of the blue line

we have the points

(-1,-3) and (0,3)

substitute

$m=\frac{3+3}{0+1}$

$m=\frac{6}{1}=6$

step 2

Find the slope of the red line

we have the points

(3,-3) and (4,2)

substitute

$m=\frac{2+3}{4-3}$

$m=\frac{5}{1}=5$

step 3

Find the slope of the green line

we have the points

(-4,-1) and (2,-2)

substitute

$m=\frac{-2+1}{2+4}$

$m=-\frac{1}{6}$

step 4

Compare the slopes

Blue line ----> $m=6$

Red line ----. $m=5$

Green line ---> $m=-\frac{1}{6}$

so

The slope of the blue line and the green line are opposite reciprocal ( their product is equal to -1)

therefore

The lines blue and green are perpendicular

7 0

3 years ago