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ddd [48]
3 years ago
15

Please help me soon!! 10 points common plzzz!

Mathematics
1 answer:
solong [7]3 years ago
4 0

Answer:

x + y = 3 x - y = 1 --------- 2x + 0y = 4 2x = 4 (2x)/2 = 4/2 x = 2

Step-by-step explanation:

hope i am right

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Solve the equation for the variable.<br><br><img src="https://tex.z-dn.net/?f=%20-%205v%20%2B%209%20%3D%20%20-%20v%20%2B%2017" i
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Answer:

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Step-by-step explanation:

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What is the complex conjugate of 13-21i?
irga5000 [103]

Answer:

To find a complex conjugate, simply change the sign of the imaginary part (the part with the i). This means that it either goes from positive to negative or from negative to positive.

As a general rule, the complex conjugate of <span>a+bi</span> is <span>a−bi</span>.

Therefore, the complex conjugate of <span>3−2i</span> is <span>3+2i</span>.

Hope this helped!!... :D

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3 0
3 years ago
Read 2 more answers
How do I round to the nearest cent with this number? 0.19125
LekaFEV [45]

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5 0
3 years ago
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Seorang pemilik toko sepatu ingin mengisi tokonya dengan sepatu laki-laki paling sedikit 100 pasang dan sepatu wanita paling sed
taurus [48]

Answer:

<em>The biggest profit that can be obtained by the shop owner= </em>IDR 2,750,000.

Step-by-step explanation:

We need to form a LPP( Linear Programming Problem) for the following problem and solve it to get the maximize the profit.

Let x denote the number of men's shoe and y denote the number of female shoes.

Maximize z= 10000x+5000y----------(1)

             x≥100 ( since a shoe store owner wants to fill his shop with at least    100 pairs of men's shoes )

            y≥150  (at least 150 pairs of women's shoes).

also x+y≤400   (The store can only accommodate 400 pairs of shoes).

         x≤150    (male shoes should not exceed 150 pairs).

⇒         100≤x≤150

Hence the optimal solution of an LPP always lie on the end points.

We have end points as:

(100,300), (150,250), (100,150),(150,150).

by putting these value in equation (1) we see which give the maximum solution.

for (100,300) i.e. x=100 and y=300:   z=2,500,000

for (150,250) i.e. x=150 and y=250:  z=2,750,000

for (100,150) i.e. x=100 and y=150: z=1,750,000

for (150,150) i.e. x=150 and y=150: z=2,250,000

Hence maximum profit is obtained at x=100 and y=300.

i.e. to maximize the profit:

<em>Number of men's shoes to be kept in store=100</em>

<em>and number of women's shoes to be kept in store=300</em>

<em>The biggest profit that can be obtained by the shop owner= </em>IDR 2,750,000.

5 0
3 years ago
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