Please anyone help question 3a(i) and (ii) I will mark brainliest answer

Select the correct answer.

iris [78.8K]

The future value of $1,000 invested at 8% compounded semiannually for five years is $\bold{\$ 1,480}$

Solution:

$\bold{A = P (1 + i )^{n}}$ ----------- equation 1

A = future value

P= principal amount

i = interest rate

n = number of times money is compounded

P = 1000

i = 8 %

$\mathrm{n} = \text { compounding period } \times \text {number of years}$

(Compounding period for semi annually = 2)

$\mathrm{n} = \text { compounding period } \times \text {number of years}$

Dividing “i” by compounding period

$i = \frac{8 \%}{2} = 0.04$

Solving for future value using equation 1

$\begin{array}{l}{A = 1000(1 + 0.04)^{10}} \\\\ {=1000 (1.04)^{10}}\end{array}$

$= 1480.2$

$\approx 1,480 \$$

3 0

3 years ago

⚠️⚠️⚠️⚠️BREAKING NEWS A METEOR IS COMING DIRECTLY TOWARDS EARTH THEY ONLY WAY TO STOP THIS METEOR IS BY ANSWERING THIS QUESTION

8090 [49]

The relation {(-1 , 3), (4 , 2), (-1 , 5)} is not a function ⇒ 2nd

Step-by-step explanation:

Let us revise the meaning of relation and function

The relation is a set of inputs and outputs
A function is a relation with one output for each input, that means every x has only one y
Ex: {(2 , 3) , (-1 , -2) , (3 , 2)} is a function because 2 has only 3 , -1 has only -2 and 3 has only 2, {(1 , 7) , (2 , -4) , (1 , -3)} is not a function because 1 has 7 and -3

The relation is a function if and only if every x has only one y

In {(0 , 0), (1 , 0), (2 , 0)}

∵ x = 0 has y = 0

∵ x = 1 has y = 0

∵ x = 2 has y = 0

∴ Every x has only one y

∴ {(0 , 0), (1 , 0), (2 , 0)} is a function

In {(-1 , 3), (4 , 2), (-1 , 5)}

∵ x = -1 has y = 3

∵ x = 4 has y = 2

∵ x = -1 has y = 5

∴ x = -1 has y = 3 and 5

∴ Not every x has only one y

∴ {(-1 , 3), (4 , 2), (-1 , 5)} is not a function

In {(1 , 2), (3 , -5), (-1 , 7)}

∵ x = 1 has y = 2

∵ x = 3 has y = -5

∵ x = -1 has y = 7

∴ Every x has only one y

∴ {(1 , 2), (3 , -5), (-1 , 7)} is a function

In {(7 , -1), (3 , -2), (5 , -2)}

∵ x = 7 has y = -1

∵ x = 3 has y = -2

∵ x = 5 has y = -2

∴ Every x has only one y

∴ {(7 , -1), (3 , -2), (5 , -2)} is a function

The relation {(-1 , 3), (4 , 2), (-1 , 5)} is not a function

Learn more:

You can learn more about the relations and functions in brainly.com/question/10570041

#LearnwithBrainly

6 0

3 years ago

Use the measurements of the scale drawing and original to calculate the scale factor, and then use the scale factor to find the

mina [271]

??????????????????3456

5 0

3 years ago

Read 2 more answers

Figure 3 2n + 10 140 4n -40 80 2n 3n - 20 I need help

abruzzese [7]

Answer:

2n +10= 140

4n- 40= 80

2n= 3n - 20

Step-by-step explanation:

it is the am progression or sum progression

3 0

2 years ago

Factor each polynomial. Look for a GCF first

weeeeeb [17]

Answer:

20. $x\left(x-6\right)\left(x+8\right)$

22. $2\left(x+1\right)\left(x+4\right)$

24. $5m\left(m-1\right)\left(m+7\right)$

Step-by-step explanation:

20. $x^3+2x^{2} -48x$

The GCF is x, so you group it out of the equation first.

$x(x^{2} +2x-48)$

Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.

$?+?=2\\?*?=-48$

The two numbers would be -6 and 8. You then differentiate the squares.

$x\left(x-6\right)\left(x+8\right)$

22. $2x^{2} +10x+8$

The GCF is 2, so you must group it out.

$2(x^{2} +5x+4)$

Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.

$?+?=5\\?*?=4$

The two numbers would be 1 and 4. Finally, differentiate the squares.

$2\left(x+1\right)\left(x+4\right)$

24. $5m^{3} +30m^2-35m$

The GCF is 5m, so you must group it out.

$5m(m^2+6m-7)$

Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.

$?+?=6\\?*?=-7$

The two numbers would be -1 and 7. Finally, differentiate the squares.

$5m\left(m-1\right)\left(m+7\right)$

7 0

2 years ago