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djyliett [7]
3 years ago
13

Please anyone help question 3a(i) and (ii) I will mark brainliest answer

Mathematics
1 answer:
Alex73 [517]3 years ago
7 0

Answer:

i) is correct answer i think

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J. Reexamine the sequence 20, 14, 8, 2, ... from the problem
DENIUS [597]

Answer:

The n th of the given sequence is t_{n} = 26-6 n

Step-by-step explanation:

<u>Step 1</u> :-

Given sequence is 20,14,8,2,.......this sequence in arithmetic progression but this sequence is decreasing sequence.

given first term is 20 and difference isd = second term- first term = 14-20=-6

now the nth term of given sequence is

by using formula t_{n}=a+(n-1)d

t_{n}= 20+(n-1)(-6)

t_{n}= 20-6 n+6

final answer:-

t_{n} = 26-6 n

<u>verification</u>:-

t_{n} = 26-6 n

put n=1 we get first term is 20

put n=2 we get second term is 14

put n=3 we get third term is 8

put n=4 we get fourth term is 2

so the n th term of sequence is

t_{n} = 26-6 n

3 0
3 years ago
X^2+4x-11=0 what is the solution set?
Sauron [17]

Answer:

The solution set can be calculatedby the following steps;

Step-by-step explanation:

5 0
2 years ago
Allison has 1/2 cup of yogurt for making fruit parfaits.Each parfait requires 1/8 a cup of yogurt.How many parfaits can she make
cupoosta [38]
Allison can make 4 fruit parfaits.

Since one parfait requires 1/8 cup of yogurt, add:
1/8 + 1/8 + 1/8 + 1/8

They all share a common denominator, so:

1/8 + 1/8 +1/8 + 1/8 = 4/8

Simplify your answer (divide numerator and denominator by the common factor of 2) :

4/8 = 1/2

1/2 represents the total amount of cups of yogurt used. Since it took adding 1/8 four times that represents 4 parfaits.
5 0
3 years ago
If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then which statement would be true
Bumek [7]
If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then the figure must be a rhombus because it has exactly 2 pairs of congruent angles.

I hope this helps! :)
3 0
3 years ago
Read 2 more answers
Solve using factoring
irina1246 [14]

Answer: you can use Photomath


Step-by-step explanation:


4 0
3 years ago
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