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3 years ago

PLS HELP THIS IS HARD ANYONE PLS

Mathematics

2 answers:

Vlada [557]3 years ago

5 0

Answer:

Step-by-step explanation:

To find:

The range of the function.

Solution:

If a function is translated 3 unit

(x,y) to (x,y - 3)

Using this rule, we get

(0,4) to (0,4 - 3)

(0,4) to (0.1)

Similarly,

(- 5,8) to ( - 5,5)

(4, - 2) to (4, - 5)

The range is of the given function is (0, 1), (-5, 5), (4, -5).

correct answer is A

The range of the given function is (0, 1), (-5, 5), (4, -5).

asambeis [7]3 years ago

3 0

Should be the last one.

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Answer asap please

Oduvanchick [21]

Answer:

(0,1) and (-2,9)

Step-by-step explanation:

A point (x,y) lies on the graph of f(x) = $(\frac{1}{3} )^{x}$ if it satisfies the condition y = $(\frac{1}{3} )^{x}$

x = 0 and y = 1.

This point satisfies the required condition as

$(\frac{1}{3} )^{0}$ = 1

Hence, this point <u>is</u> on the graph of f(x) = $(\frac{1}{3} )^{x}$

x = 3 and y = 27.

This point doesn't satisfy the required condition as

$(\frac{1}{3} )^{3}$ = $\frac{1}{27}$ ≠ 27

Hence, this point i<u>s not</u> on the graph of f(x) = $(\frac{1}{3} )^{x}$

x = -2 and y = 9.

This point satisfies the required condition as

$(\frac{1}{3} )^{-2}$ = $3^{2}$ = 9

Hence, this point <u>is</u> on the graph of f(x) = $(\frac{1}{3} )^{x}$

x = -1 and y = $-\frac{1}{3}$ .

This point satisfies the required condition as

y = $(\frac{1}{3} )^{-1}$ = $3^{1}$ = 3 ≠ $-\frac{1}{3}$

Hence, this point <u>is not</u> on the graph of f(x) = $(\frac{1}{3} )^{x}$

7 0

3 years ago

The sum of the digits of the number 2016 is 9.What is the least number greater than 2016 whose sum of the digits is 9

lozanna [386]

Answer:

2025 if Im not wrong...

Step-by-step explanation:

6 0

4 years ago

How to simplify the expression <br> 10h+6-5h+3

marin [14]

Answer:

You just have to combine terms

Step-by-step explanation:

10h + 6 - 5h +3 can be written as:

10h - 5h + 3 + 6 (now all you have to do is combine terms)

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3 years ago

Complete the statement, and find the value of x in the diagram. <br> help please!

hodyreva [135]

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8 0

2 years ago

Read 2 more answers

What is the center of the circle and the radius of 2x^2 - 12x +2y^2 +8y = 10

DedPeter [7]

Answer:

the center of the circle, (h, k), is (3, -2),

and the radius is √18, or 3√2.

Step-by-step explanation:

This problem becomes much easier if you divide it through by 2:

x^2 - 6x +y^2 +4y = 5

Next, regroup this equation so that the x terms are together and the y terms are also together, separately:

x^2 - 6x + y^2 + 4y = 5

Next, complete the square of x^2 - 6x:

x^2 - 6x → x^2 - 6x + 9 - 9 → (x - 3)^2 - 9.

Then complete the square of y^2 + 4y:

y^2 + 4y + 4 - 4 → (y + 2)^2 - 4

Now rewrite x^2 - 6x + y^2 + 4y = 5 as

(x - 3)^2 - 9 + (y + 2)^2 - 4 = 5

Next, group the constants together on the right side:

(x - 3)^2 - 9 + (y + 2)^2 - 4 = 5 → (x - 3)^2 + (y + 2)^2 = 18

Comparing this result to the standard equation of a circle:

(x - h)^2 + (y - k)^2 = r^2,

we see that h = 3, y = -2 and r^2 = 18.

Thus, the center of the circle, (h, k), is (3, -2),

and the radius is √18, or 3√2.

6 0

3 years ago