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3 years ago

Please help! 20 points!!!

Mathematics

2 answers:

KonstantinChe [14]3 years ago

8 0

Answer:

SOLUTION STEPS

+−6

Multiply 6 and 8 to get 48.

48+5

−

6×3+1

Add 48 and 5 to get 53.

−

6×3+1

Multiply 6 and 3 to get 18.

−

18+1

Add 18 and 1 to get 19.

−

Least common multiple of 8 and 3 is 24. Convert

and

to fractions with denominator 24.

159

−

152

Since

159

and

152

have the same denominator, subtract them by subtracting their numerators.

159−152

Subtract 152 from 159 to get 7.

Step-by-step explanation:

devlian [24]3 years ago

6 0

Answer:

$\frac{7}{24}$

Step-by-step explanation:

$6 \frac{5}{8} + \bigg( - 6 \frac{1}{3} \bigg ) \\ \\ = 6 \frac{5}{8} - 6 \frac{1}{3} \\ \\ = \frac{6 \times 8 + 5}{8} - \frac{6 \times 3 + 1}{3} \\ \\ = \frac{48 + 5}{8} - \frac{18 + 1}{3} \\ \\ = \frac{53}{8} - \frac{19}{3} \\ \\ = \frac{53 \times 3 - 19 \times 8}{8 \times 3} \\ \\ = \frac{159 - 152}{24} \\ \\ = \frac{7}{24}$

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm2/m

Mnenie [13.5K]

Answer:

The base is reducing at a rate of 3.4cm per min.

Step-by-step explanation:

Let The Height of the Triangle, h

Area of the triangle = A

Area of a Triangle, $A= \frac{1}{2}bh$

When $A=190 cm^2, h=10cm$

$190= \frac{1}{2}*b*10\\b=38cm$

$\frac{dA}{dt}=\frac{1}{2}h\frac{db}{dt}+ \frac{1}{2}b\frac{dh}{dt}\\\frac{dh}{dt}=1 cm/min, \frac{dA}{dt}=2cm^2/min,$

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3 years ago

Suppose a triangle has sides a, b, and c and the angle opposite the side of length a is acute what must be true?

ANTONII [103]

The true statement about the triangle is (a) b^2 + c^2 > a^2

<h3>How to determine the true inequality?</h3>

The sides are given as:

a, b and c

The angle opposite of side length a is an acute angle

The above means that:

The side a is the longest side of the triangle.

The Pythagoras theorem states that:

a^2 = b^2 + c^2

Since the triangle is not a right triangle, and the angle opposite a is acute.

Then it means that the square of a is less than the sum of squares of other sides.

This gives

a^2 < b^2 + c^2

Rewrite as:

b^2 + c^2 > a^2

Hence, the true statement about the triangle is (a) b^2 + c^2 > a^2