In arithmetic sequence, let the first tern of the arithmetic sequence be, a, and the common difference, d, then the nth term, Tn, of the arithmetic sequence is given by:
![T_n=a+(n-1)d](https://tex.z-dn.net/?f=T_n%3Da%2B%28n-1%29d)
For a linear function with y-intercept, c, and slope, m, the linear function is given by:
![y=mx+c](https://tex.z-dn.net/?f=y%3Dmx%2Bc)
Comparing the equation of the arithmetic sequence and that of the linear function, we can see that y is compared to Tn, a is compared to c, m is compared to d, and x is compared to n - 1.
Therefore, <span>the common difference in an arithmetic sequence is like the slope of a linear function as both are multiple of a variable.</span>
The probability is (1/6)^5 power. Since the locks are independent of each other, you can multiply the probabilities together. There are 6 possible numbers for each lock and there are 5 locks. So the probability is (1/6)^5 power.<span />
Answer:
Solution given:
m∠ADB=(4x−12)°
m∠CDB=(3x+6)°
m∠ADC =?
Since diagonal BD bisect the angle <ADC
so
m∠ADB= m∠ADC
(4x-12)°=(3x+6)°
4x-3x=6-12
x=12+6
x=18°
again.
<ADB=m∠ADB+ m∠ADC=4×18-12+3×18+6=120°
So
<u>the m∠</u><u>ADC</u><u> </u><u>=</u><u>1</u><u>2</u><u>0</u><u>°</u>
<span>-12+2b=12-6b
-12+8b=12
8b=24
b=3</span>
Answer:
hope this can help you (^^)