The given complex number is ⇒ z = a + b i
The absolute value of z = √( a² + b² ) = 3.28
So, we will check which of the options will give 3.28
<span>( A) IF ⇒⇒ a=1.5 and b=1.7
</span>
<span>∴ √( a² + b² ) = √( 1.5² + 1.7²) = √5.14 ≈ 2.27
</span>
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<span>(B) IF ⇒⇒ a=1.5 and b=3.3
</span>
<span>∴ √( a² + b² ) = √(1.5² + 3.3²) = √13.14 ≈ 3.62
</span>
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<span>(C) IF ⇒⇒ a=1.7 and b=2.8
</span>
<span>∴ √( a² + b² ) = √(1.7² + 2.8²) = √10.73 ≈ 3.28
</span>
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<span>(D) IF ⇒⇒ a=2.8 and b=3.3
</span>
∴ √( a² + b² ) = √(2.8² + 3.3²) = √18.73 ≈ 4.33
=====================================
So, the correct answer is option (C) <span>a=1.7,b=2.8</span>
The numbers divisible by 3 are multiples of 3.
Answer:
Two standard deviations
Step-by-step explanation:
The Z score is obtained using the mean and standard deviation, according to the empirical. Rule, which gives percentage of values that lie within an interval estimate in a normal distribution ;
one standard deviation lie within 68% of the mean
Two standard deviations lie within 95%
Three standard deviations lie within 99.7%
Hence, for the question given, 95% fall within 2 standard deviations of the mean
113.4-18=95.4
So 95.4+18=113.4
Hope that was useful and best of wishes!!
Answer:
277,200
Step-by-step explanation:
To find the number of permutation we can form from the letters of the word "engineering", we first need to find the frequencies of the different letters present.
E = 3
G = 2
N= 3
I = 2
R = 1
Now that we have the frequencies, we count the number of letters in the word "engineering".
E N G I N E E R I N G
11 letters
Now we take the factorial of total number of letters and divide it by the number of repeats and their factorial
So we get:
We remove the 1! because it will just yield 1.
So the total number of permutations from the letters of the word "engineering" will be:
Total number of permutations = 
Total number of permutations = 277,200
