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3 years ago

Jay played 350 solitaire games he won 154 of those games. What percent of the games did Jay win?

Mathematics

2 answers:

Soloha48 [4]3 years ago

7 0

Answer:

44.044

Step-by-step explanation:

To find the answer we first have to find the value of each percent, to do this we divide 100 by 350, that gets us approximately 0.286. We know that he won 154 of them we then multiply 154 by 0.286 to get the percentage of games he won and we get 44.044.

Sholpan [36]3 years ago

7 0

44%
154/350=0.44
0.44=44%

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3 years ago

What is the slope intercept from for 16x+9y=40

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Here, the given equation is 16 x + 9 y = 40

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3 years ago

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The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

<h3>How to determine the rational root of the function f(x)?</h3>

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

For a function P(x) such that

P(x) = ax^n +...... + b

The rational roots of the function p(x) are

Rational roots = ± Possible factors of b/Possible factors of a

In the function f(x), we have:

a = 3

b = 6

The factors of 3 and 6 are

a = 1 and 3

b = 1, 2, 3 and 6

So, we have:

Rational roots = ±(1, 2, 3, 6)/(1, 3)

Split the expression

Rational roots = ±(1, 2, 3, 6)/1 and ±(1, 2, 3, 6)/3

Evaluate the quotient

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3, 1, 2)

Remove the repetition

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3)

Hence, the rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

The complete parameters are:

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)