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2 years ago

-[24/6 + (-8)(2)^2-3] +92

2 answers:

3 0

$( \frac{ - 24}{6} + ( - 8)(2) {}^{2} - 3) + 92 \\ ( - 4) + ( - 8) \times 4 - 3 + 92 \\ ( - 4) + ( - 8) \times 4 - 96 \\ ( - 12) \times 4 - 96 \\ ( - 48) - 96 \\ = 134$

Dvinal [7]2 years ago

3 0

Hey there!

-[24/6 + (-8)(2)^2 - 3] + 92

= -(24/6 - 8(2)^2 - 3 + 92

= -(4 - 8(-2)^2 - 3 + 92

= -(4 - 32 - 3) + 92

= -(-28 - 3) + 92

= 31 + 92

= 123

Therefore, your answer is: 123

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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Laura's age is 9 years.

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Let x be the age of April.

Laura's age = 2 years more than half of April's age

<u>Convert statement into algebraic expression:</u>

Half of April's age = $\frac{x}{2}$

2 years more than half of April's age = $\frac{x}{2}+2$

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$$\Rightarrow \ \ x+(\frac{x}{2}+2) =23$

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$$\Rightarrow \ \ \frac{x}{1}+\frac{x}{2}+\frac{2}{1} =23$

To add the fractions make the denominators same.

Multiplying 2 on both numerator and denominator of unlike terms, we get

$$\Rightarrow \ \ \frac{x\times2}{1\times2}+\frac{x}{2}+\frac{2\times2}{1\times2} =23$

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Do cross multiplication.

$$\Rightarrow \ \ 2x+x+4=23\times2$

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$$\Rightarrow \ \ 3x=42$

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Aprils's age = 14 years

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= 7 + 2

Laura's age = 9

Hence Laura's age is 9 years.

8 0

3 years ago

-[24/6 + (-8)(2)^2-3] +92​

-[24/6 + (-8)(2)^2-3] +92