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3 years ago

I am in sixth and i have final exams can u pls help me out? question: what is 7000 divided by 95? pls help meh

Mathematics

2 answers:

olchik [2.2K]3 years ago

4 0

Anwer: I think it's 73 13/19

Hope this helped!

topjm [15]3 years ago

3 0

Answer:

73.6842105263

Step-by-step explanation:

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Which of the angles are corresponding angles?

lord [1]

Answer:

E and F

Step-by-step explanation:

1 and 5

3 and 7 are corresponding angles.

A pair of angles on the same side of the transversal, one of which is an interior angle and the other one is an exterior angle but do not form a linear pair is known as corresponding angles

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3 years ago

Given a 13-card bridge hand has been dealt from a standard deck of 52 cards, what is the probability of having exactly 6 hearts

frosja888 [35]

$P(6\ hearts)=\frac{13C6\times 39C7}{52C13}=0.0416$

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3 years ago

PLEASE HELP FAST PLEASE AND THANK YOU HELP MY SISTER MEH

Gnoma [55]

The answers are B , D , and F

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3 years ago

A telephone company charges a fixed monthly rate plus a rate per minute of usage. The company charges $155 for 100 minutes of us

torisob [31]

Answer:

The answer is D.

Step-by-step explanation:

As said in the problem, we are labeling the total minutes used <em>x </em>and the total monthly income as <em>y</em>. This means that in the graph we will be making the y-axis should represent the total monthly charges, and the x-axis should represent the total minutes.

Thus the graph should go through points (100,155) and (200,245) and its slope is:

$\frac{245-155}{200-100} =0.9.$

8 0

3 years ago

Read 2 more answers

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

3 years ago