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Burka [1]
3 years ago
14

I am in sixth and i have final exams can u pls help me out? question: what is 7000 divided by 95? pls help meh

Mathematics
2 answers:
olchik [2.2K]3 years ago
4 0

Anwer: I think it's 73 13/19

Hope this helped!

topjm [15]3 years ago
3 0

Answer:

73.6842105263

Step-by-step explanation:

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Which of the angles are corresponding angles?
lord [1]

Answer:

E and F

Step-by-step explanation:

1 and 5  

3 and 7 are corresponding angles.

A pair of angles on the same side of the transversal, one of which is an interior angle and the other one is an exterior angle but do not form a linear pair is known as corresponding angles

4 0
3 years ago
Given a 13-card bridge hand has been dealt from a standard deck of 52 cards, what is the probability of having exactly 6 hearts
frosja888 [35]
P(6\ hearts)=\frac{13C6\times 39C7}{52C13}=0.0416
7 0
3 years ago
PLEASE HELP FAST PLEASE AND THANK YOU HELP MY SISTER MEH
Gnoma [55]
The answers are B , D , and F
3 0
3 years ago
A telephone company charges a fixed monthly rate plus a rate per minute of usage. The company charges $155 for 100 minutes of us
torisob [31]

Answer:

The answer is D.

Step-by-step explanation:

As said in the problem, we are labeling the total minutes used <em>x </em>and the total monthly income as <em>y</em>. This means that in the graph we will be making the y-axis should represent the total monthly charges, and the x-axis should represent the total minutes.

Thus the graph should go through points (100,155) and (200,245) and its slope is:

\frac{245-155}{200-100} =0.9.

8 0
3 years ago
Read 2 more answers
A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the
Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

             P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample average age = 25 years

            \sigma = population standard deviation = 1.8 years

            n = sample of students = 36

            \mu = population average age

So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

                                                  = [ 25 - 2.3263 \times {\frac{1.8}{\sqrt{36} } , 25 + 2.3263 \times {\frac{1.8}{\sqrt{36} } ]

                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0
3 years ago
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