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Natasha2012 [34]
3 years ago
4

I don't know how to solve this. x/6 - 3 = 2 + x

Mathematics
1 answer:
fomenos3 years ago
5 0

Answer:

x=-6

Step-by-step explanation:  

Find common denominator

x/6-3=2+x

x/6  6(-3)

 6      6  =2+x

Combine fractions with common denominator

x/6  6(-3)

6        6 =2+x

x+6(-3)

   6 =2+x

Multiply the numbers

x+6(-3)

     6=2+x

x-18

6=2+x

PLEASEEE GO TO MY PAGE I REALLY NEEED HELP ON THIS TEST ITS WAY PASSED DUE PLSS

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Also need help with this question
Masja [62]

Answer:

C

Step-by-step explanation:

In option c, the first block is divided into 3 pieces where 2 parts are shaded whereas the second block is divided into 6 pieces where 3 parts are shaded

For both to be equivalent, both of them should be the same

2/3 = x/6

x = 4

4 pieces should be shaded in in the second block to be equal to the first one, in the diagram only 3 parts are shaded thus the answer is c

8 0
2 years ago
Y is directly proportional to x and k is a constant. Which equation
inn [45]
It would be Y=kx.
Look at photo for explanation

7 0
3 years ago
Read 2 more answers
Factor the trinomial below x^2+7x-30
Triss [41]

Answer:

(x + 10)(x - 7)

Step-by-step explanation:

It is 3 and 10 in some order. The difference is 7 and it is plus, so the larger number is +10 and the smaller one - 3

(x + 10)(x - 3) should be the answer

10x - 3x = 7x

5 0
4 years ago
26347+13595= algorithm
fgiga [73]
39942 there's your answer kiddo.
3 0
3 years ago
Read 2 more answers
A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly locat
DiKsa [7]

Answer:

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let \mu be the random variable that follows a Poisson distribution, then mean \mu = \dfrac{10}{500}= 0.02

and the mean that the random selection of 50 pages will contain no error is \lambda = 50 \times 0.02 =1

∴

Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}

Pr(q =0) = 0.368

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )]    since it is less than 2

P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]

P(X \geq 2) = 1 - [0.3678 +0.3678]

P(X \geq 2) = 1 -0.7356

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

6 0
4 years ago
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